What is the Pemdas answer for 5-0×3+9÷3

2 answers:

7 0

Multiplication first, division second, subtraction third, addition fourth.
(Because M/D is before A/S and you do it from left to right.)

So it would be 5 - (0×3) + (9÷3)

Which is also (5 - 0) + 3.

So the final answer is 8, as 5 + 3 is 8.

padilas [110]3 years ago

6 0

PEMDAS
since we don't have exponentes or paretnahsees we do
muliplictaion or division whichever comes first (since division is just multiplication of a fraction)

addition or subtraction whichever comes first (since subtraction is adding a negative)

so
multiply/divide
0 times 3=0
9/3=3

now we have
5-0+3
add/subtract
5-0=5
5+3=8
answer is 8

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Kitty [74]

Answer: (-2, 5) and (2, -3)

<u>Step-by-step explanation:</u>

Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:

y - intercept = (0, 1) 2nd point = ( -1, 1).

Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

$y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\$