50%. students (in percent) who passed the second exam also passed the first exam.
Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.
Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.
Thus, both tests were passed by 40 of the 80 pupils who passed the second one:
40/80 = 1/2 = 50%.
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Answer: 7
Step-by-step explanation: Imagine having 5 chocolate bars and then adding 2, or you could try counting with your fingers. Another method is writing a number line and going plus 2 from five so you can visualize it more.
Answer:
D) Abner can spend $60 per month on school clothes and $20 per month on gym clothes and stay within his budget.
Step-by-step explanation:
In the problem it states that Abner will spend 3 times more on (s)school clothes than (g) gym clothes.
So it would appear as s ≥ 3g.
If we plug in $60 as s (school clothes) and $20 as g (gym clothes), the statement is true.
60 ≥ 3(20)
60 ≥ 60. These numbers make the linear system true.
If you have trouble with this, an easy way to find this answer is simply creating the linear system that represents the problem, (he will buy 3 times more school clothes than gym clothes) s ≥ 3g and plug in each variable from the answer choices until you find the variables that make the linear system true.
<h2>C. ΔQRS ≅ ΔGFE </h2>
ΔQRS ≅ ΔGFE because :
∠Q = ∠G = 55°( corresponding part )
∠R = ∠F = 60° ( corresponding part )
∠S = ∠E = 65° ( corresponding part )
QS = GE = 16 ( corresponding part )
Therefore , the correct answer is :-
<h3>C. ΔQRS ≅ ΔGFE </h3>
