Question

7p-(3p+4) = -2(2p-1)+10 Please answer!!!!!!!

Answer 1

P=2
Work:
7p−(3p+4)=−2(2p−1)+107p−(3p+4)=−2(2p−1)+107p+−1(3p+4)=−2(2p−1)+107p+−1(3p)+(−1)(4)=−2(2p−1)+107p+−3p+−4=−2(2p−1)+107p+−3p+−4=(−2)(2p)+(−2)(−1)+107p+−3p+−4=−4p+2+10(7p+−3p)+(−4)=(−4p)+(2+10)4p+−4=−4p+124p−4=−4p+124p−4+4p=−4p+12+4p8p−4=128p−4+4=12+48p=168p8‌=‌168‌p=2

Hope this helps:)

Answer 2

7p-(3p+4)=-2(2p-1)+10
7p-3p-4=-4p+2+10
4p-4=-4p+12
4p-4+4=-4p+12+4
4p=-4p+16
4p+4p=-4p+16+4p
8p=16
8p/8=16/8
p=2