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tankabanditka [31]
3 years ago
11

Explain how to write and evaluate an algebraic expression.

Mathematics
2 answers:
BabaBlast [244]3 years ago
8 0
So you would start with 40/n because quotient means division and then it would be (40/n) - 13  (40 divided by n then minus 13) because the answer is thirteen less than the quotient of those numbers. since it wants you to evaluate for n=2 you would do 40/2 which is 20 then subtract 13 which is 7.

So write the expression as (40/n) -13 and when you evaluate just stick the 2 where the n is for (40/2) - 13
                                20 - 13
                                   = 7 
Svetradugi [14.3K]3 years ago
5 0
40. 40
------ -13 ------ -13. 20-13. 7
N 2
You would write this this by just looking at the key terms like for example (13 less than) which means it's being subtracted. And (quotient of 40 and a number) means that it's going to be a fraction with 40 at the top and n on the bottom. It's really simple once you get practice hope this helps :)
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Read 2 more answers
Write the equation in siope-intercept form for the line that passes through the given pointand is perpendicular to the given equ
yulyashka [42]

For a line in the form:

\begin{gathered} ax+by=c \\ The\text{ slope m is:} \\ m=-\frac{a}{b} \end{gathered}

In this case, for the line 2x + 10y = 20 with a=2 and b=10 the slope is:

\begin{gathered} m_1=-\frac{a}{b}=-\frac{2}{10} \\ m_1=-\frac{1}{5} \end{gathered}

Now, two lines are perpendiculars if the slopes satisfy the following equation:

m_2=-\frac{1}{m_1}

So, for the line we want the slope is:

\begin{gathered} m_1=-\frac{1}{5} \\ m_2=-\frac{1}{m_1}=-\frac{1}{(-\frac{1}{5})}=5 \end{gathered}

Finally, the line pass througth the point (2, 3) with slope m=5, so the equation is:

\begin{gathered} P_1=(2,3),m=5 \\ y=mx+b \\ \text{The P1 must satisfy the equation:} \\ 3=5\cdot2+b \\ b=3-10 \\ b=-7 \end{gathered}

The equation of the line is y = 5x - 7

7 0
1 year ago
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