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3 years ago

Find the values of x that satisfy

Mathematics

1 answer:

mr_godi [17]3 years ago

7 0

Setup 2 problems
2x - 7 < 15   and    2x - 7 > -15
2x < 22                  2x > -8
x < 11                    x > -4

Or you can write it -4 < x < 11

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May I know why is the answer 1/2? Any idea <br><br> Thank you!

ElenaW [278]

let's put value of t in equation.

x = 2√t

x = 2√y

x/2 = √y

(x/2)^2 = y

y = x^2 /4

now let's differentiate it with respect to x.

dy/dx = 2x/4 = x/2

differentiating again wrt to x

d^2y/dx^2 = 1/2

8 0

2 years ago

Find the area of the figure below

sergiy2304 [10]

Answer:

Step-by-step explanation:

break shape into two parts

rectangle - 4*3=12

triangle 6*5/2 = 15

add rect and triangle tgt - 12+15=27

6 0

2 years ago

Work out giving your answer in its simpliest form 2/3 × 3 3/5<br>help asap I will give brainlist

Anna11 [10]

Answer:

2 2/5 or 12/5

Step-by-step explanation:

Hope this helps :)

5 0

2 years ago

Read 2 more answers

Write a division expression with a quotient that is: greater than 8÷0.001 less than 8÷0.001 between 8÷0.001 and 8÷110 does one b

Anna71 [15]

Answer:

9÷0.001 is greater than 8÷0.001.

7÷0.001 is less than 8÷0.001.

8÷0.002 lie between 8÷0.001 and 8÷110.

Step-by-step explanation:

The division expression which is greater than 8÷0.001 is:

9÷0.001

Since, the numerator of the number 9÷0.001 is greater than 8÷0.001. and as their denominator is same.

so, the number whose numerator is greater than the other will result in the overall number to be greater.

The division expression which is less than 8÷0.001 is 7÷0.001.

Since, for two numbers with same denominator the number whose numerator is smaller is smaller than the other.

The division expression that lie between 8÷0.001 and 8÷110 is: 8÷0.002.

Since 8÷0.002 is greater than 8÷110, as for two numbers with same numerator but different denominator the number whose denominator is greater is a smaller number.

similarly 8÷0.002 is smaller than 8÷0.001.

8 0

3 years ago

The probability that a new car battery functions for more than 10,000 miles is .8, the probability that it functions for more th

MAXImum [283]

Answer:

There is a 50% probability that its total life will exceed 20,000 miles.

Step-by-step explanation:

To solve this question, we use the following formula:

$P(A|B) = \frac{P(A \cap B)}{P(B)}$

In which P(A|B) is the probability of A happening, given that B has happened, $P(A \cap B)$ is the probability of A and B happening, and P(B) is the probability of B happening.

In this problem, we want:

The probability of the total life of the car battery exceeding 20,000 miles, given that it exceeded 10,000 miles.

$P(A \cap B)$ is the probability of exceeding 20,000 and 10,000 miles. It is the same as the probability of exceeding 20,000 miles(If it exceeded 20,000 miles, necessarily it will have exceeded 10,000 miles). So $P(A \cap B) = 0.4$

P(B) is the probability of exceeding 10,000 miles. So $P(B) = 0.8)$

$P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.4}{0.8} = 0.5$

There is a 50% probability that its total life will exceed 20,000 miles.

6 0

3 years ago