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RUDIKE [14]
3 years ago
12

The equation of the line passing through points (5,7) and (-15,23) is

Mathematics
1 answer:
sertanlavr [38]3 years ago
4 0
I think it must be this,<span><span>4<span>√41</span></span>≈25.61249694</span><span><span>4⁢41</span>≈<span>25.61249694</span></span>
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Please anyone I’ll mark as a branlist
Makovka662 [10]

Answer:

the first option is the answer, r = √6

Step-by-step explanation:

hypotenuse =  \sqrt{opposite {}^{2}  + adjacent {}^{2} }

hypotenuse = q = √12

adjacent = p = √6

opposite = r

substitute the values into the hypotenuse formula

q =  \sqrt{r {}^{2}  + p {}^{2} }

\sqrt{12} =  \sqrt{r {}^{2}  + ( \sqrt{6} ) {}^{2} }

( \sqrt{12} ) {}^{2}  = r {}^{2}  +6

12 = r {}^{2}  + 6

12 - 6 = r {}^{2}

6 = r {}^{2}

\sqrt{6}  = r

r =  \sqrt{6}

4 0
3 years ago
Equivalent fractions of 3/4?
zhannawk [14.2K]
6/8, 9/12, 12/16, 30/40, 60/80
4 0
3 years ago
Read 2 more answers
How do you do this question?
Nikitich [7]

Answer:

-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C

Step-by-step explanation:

∫ 15 sin(√(at)) dt

Use substitution:

If x = √(at), then:

dx = ½ (at)^-½ (a dt)

dx = a / (2√(at)) dt

dx = a/(2x) dt

dt = (2/a) x dx

Plugging in:

∫ 15 sin x (2/a) x dx

30/a ∫ x sin x dx

Integrate by parts:

If u = x, then du = dx.

If dv = sin x dx, then v = -cos x.

∫ u dv = uv − ∫ v du

= 30/a (-x cos x − ∫ -cos x dx)

= 30/a (-x cos x + ∫ cos x dx)

= 30/a (-x cos x + sin x + C)

Substitute back:

30/a (-√(at) cos(√(at)) + sin(√(at)) + C)

-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C

3 0
3 years ago
How do I set up this problem
Molodets [167]

Set up a ratio to compare the values, then solve for the missing value (y):


\frac{53}{-265} = \frac{y}{-335} \\y = 53(-335) / -225\\y = -17755 / -225\\y = 67:


4 0
4 years ago
Y = 2x + 7
True [87]

Answer:

Infinite solutions

Step-by-step explanation:

you add 2x to both sides of the bottom equation and then BAM they are coinciding

8 0
3 years ago
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