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3 years ago

Simplify (√3 − √7)^2

Mathematics

1 answer:

Alika [10]3 years ago

3 0

Answer: 10 - 2√21

Step-by-step explanation: I simplified your question by using an online calculator. :)

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Find the area of 14 nine and eight

Reptile [31]

Answer:

Can u add the pic and I’ll answer it

Step-by-step explanation:

3 0

3 years ago

there are 6 glass bottles and eight plastic bottles on a rack. I f one is chosen at random, what is the probability of picking a

netineya [11]

Answer:

6:8

Step-by-step explanation:

6 is the ratio of glass bottles and 8 is the plastic or you can put 3:4 because you divide the number b 2

3 0

3 years ago

Sketch a graph that has the given end behavior. 13. As x → -∞, y → ∞ 14. As x → -∞, y → -∞ As x → ∞, y→∞ As x→∞, y → 0

Julli [10]

Answer:the hardest questiom

Step-by-step explanation:

6 0

2 years ago

When fishing off the shores of Florida, a spotted seatrout must be between 10 and 30 inches long before it can be kept; otherwis

Mademuasel [1]

Answer:

There is a 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches, so $\mu = 22, \sigma = 4$ .

What is the probability that a fisherman catches a spotted seatrout within the legal limits?

They must be between 10 and 30 inches.

So, this is the pvalue of the Z score of $X = 30$ subtracted by the pvalue of the Z score of $X = 10$

X = 30

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{30 - 22}{4}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

X = 10

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10 - 22}{4}$

$Z = -3$

$Z = -3$ has a pvalue of 0.00135.

This means that there is a 0.9772-0.00135 = 0.97585 = 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

3 0

2 years ago

Can I get help finshing all these qustions 1. -4(6) 2. -21-8) 3. 121-4) 4. -6(5) 5. -10(-9) 6. -(5) 7. (-5) 8. -30(5) 9. 20(-6)

Papessa [141]

Answer:

1. -4(6)= -24

2.-21-8= -29

3. 121-4 =117

4. -6(5) =-30

5. -10(-9)= 90

6. (-5)7= -35

7. (-5)8= -40

8. -30(5)= -150

9. 20(-6)= -120

10. -14(6)= -84

11. (-13)2 = -26

12. –7(15) = -105

13. -3(4) = -12

14. 7(-3) = -21

15. 3(-3) = -9

16. -2(-10) = 20

17. (-5)(-3)(4) = 60

18. -3(-3)(4)= 36

19. -3(-5) = 15

20. 5(-3) = -15

21. 7(-5)(4) = -140

22. -2(-5)(-3)= -30

23. – 10(-3)=30

24. -21-3= -24

Explanation:

We have followed the rules in adding and subtracting negative as well as positive values on the number line.

When adding two negative values, the result is a negative value.

When adding a negative and positive value, the result is either a positive or negative value depending on if the negative value is bigger or smaller than the positive value

When multiplying two negative values, the result is a positive value

When multiplying one negative and one positive value, the result is a negative value

To make you understand addition and subtraction of negative and positive numbers better, let us use a simple analogy. Assuming you are owing five oranges(-5) and you are only able to give two oranges(+2), you will still be owing 3 oranges(-3). Assuming also that you are owing 6 oranges(-6) and you are able to give 8 oranges(+8), you would have given excess oranges and would be owed two oranges(+2). Hence the results above.

8 0

3 years ago