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Karo-lina-s [1.5K]
3 years ago
5

What is the common ratio of the geometic sequence whose second and forth terms are 6 and 54, respectively?

Mathematics
2 answers:
devlian [24]3 years ago
8 0

The answer would be C.

Luda [366]3 years ago
7 0

Answer:

C

Step-by-step explanation:

The n th term formula of a geometric sequence is

a_{n} = a r^{n-1}

where a is the first term and r the common ratio

Using the second and fourth term, then

ar = 6 → (1)

ar³ = 54 → (2)

Divide (2) by (1)

\frac{ar^3}{ar} = \frac{54}{6} = 9

r² = 9 ⇒ r = \sqrt{9} = 3 → C

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Question 9. Factor x^2 - 6x + 9.
Lunna [17]

Answer:

C

Step-by-step explanation:

Given

x² - 6x + 9

Consider the factors of the constant term (+ 9) which sum to give the coefficient of the x- term (- 6)

The factors are - 3 and - 3, since

- 3 × - 3 = + 9 and - 3 - 3 = - 6, thus

x² - 6x + 9 = (x - 3)(x - 3) = (x - 3)² → C

6 0
3 years ago
Read 2 more answers
Substitute the given values of the variables into the equation. Write True or False to indicate whether the values make the open
tigry1 [53]
This is false because 2(7)+0.8/0.2=56 and 22* -4 is equal to -88 and -88 is not equal to 56
6 0
3 years ago
Pls help on both questions
WINSTONCH [101]

Answer:

Step-by-step explanation:

Both expression are the same :

14 = 2(x + 3)

By expansion :

14 = 2*x + 2*3

14 = 2x + 6

Hence ;

Both expression are the same

Weight of one circle :

Final weight on both sides are equal:

Weight on Left hand side = 14

Weight on right hand side = 3*x + 3*x

Weight on Left hand side = Weight on right hand side

14 = 3x + 3x

14 = 6x

x = 14 / 6

x = 2.333

4 0
3 years ago
Cany anybody give me the awnser to this?
Olegator [25]

Have a look at the attached image.

8 0
3 years ago
Extra help please, -7y^2-2y^2+y^3-3y-2y+5y^3-2y
nata0808 [166]

Answer:

6y^3-9y^2-7y

Step-by-step explanation:

y^3-+5t^3 - 7y^2-2y^2 - 3y-2y-2y

5 0
3 years ago
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