Ask question

Ask question

All categories

3 years ago

12

Jordyn's rectangular garden is represented in the diagram below. If a diagonal walkway crosses their garden, what is its length,

in feet?
Walkway
8 feet
15 feet

1 answer:

agasfer [191]3 years ago

3 0

Answer: 23

Step-by-step explanation:

You might be interested in

Find the coordinates of the point of intersection of the graphs of lines: y=1−2x and y=x−5

koban [17]

To find the point of intersection, you have to set them equal to each other.

$1 - 2x = x - 5\\\\-2x - x = -5 - 1\\\\-3x = -6\\\\x = 2$

To find the y-value, plug in 2 into one of the equations:

y = 2 - 5

y = -3

Point of intersection: (2, -3)

5 0

3 years ago

Integral of x"2+4/x"2+4x+3

dolphi86 [110]

I'm guessing you mean

$\displaystyle \int\frac{x^2+4}{x^2+4x+3}\,\mathrm dx$

First, compute the quotient:

$\displaystyle \frac{x^2+4}{x^2+4x+3} = 1 + \frac{4x-1}{x^2+4x+3}$

Split up the remainder term into partial fractions. Notice that

<em>x</em> ² + 4<em>x</em> + 3 = (<em>x</em> + 3) (<em>x</em> + 1)

Then

$\displaystyle \frac{4x-1}{x^2+4x+3} = \frac a{x+3} + \frac b{x+1} \\\\ \implies 4x - 1 = a(x+1) + b(x+3) = (a+b)x + a+3b \\\\ \implies a+b=4 \text{ and }a+3b = -1 \\\\ \implies a=\frac{13}2\text{ and }b=-\frac52$

So the integral becomes

$\displaystyle \int \left(1 + \frac{13}{2(x+3)} - \frac{5}{2(x+1)}\right) \,\mathrm dx = \boxed{x + \frac{13}2\ln|x+3| - \frac52 \ln|x+1| + C}$

We can simplify the result somewhat:

$\displaystyle x + \frac{13}2\ln|x+3| - \frac52 \ln|x+1| + C \\\\ = x + \frac12 \left(13\ln|x+3| - 5\ln|x+1|\right) + C \\\\ = x + \frac12 \left(\ln\left|(x+3)^{13}\right| - \ln\left|(x+1)^5\right|\right) + C \\\\ = x + \frac12 \ln\left|\frac{(x+3)^{13}}{(x+1)^5}\right| + C \\\\ = \boxed{x + \ln\sqrt{\left|\frac{(x+3)^{13}}{(x+1)^5}\right|} + C}$

3 0

2 years ago

The circumference of a circle is 18 feet. What is the area

7nadin3 [17]

Answer:

18

Step-by-step explanation:

it does not have an area its an circle so it just 18 feet

really want a crown

8 0

3 years ago

Read 2 more answers

A population of 50 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain up to 500 deer.

rewona [7]

Answer:

p1 = 70 deer

p2 = 98 deer

Step-by-step explanation:

We use the population growth expression:

$N(t)=N_0\,(1+r)^t$

which in our case renders:

$N(t)=N_0\,(1+r)^t\\N(t)=50\,(1+0.4) ^t\\N(t)=50\,(1.4) ^t$

Therefore, after 1 year the population would be:

$N(1)=50\,(1.4) ^1=70$

giving a total of 70 deer

and after two years, it would be:

$N(2)=50\,(1.4) ^2=98$

8 0

3 years ago

Help me i am having trouble

trasher [3.6K]

Yes the slope is one fourth.

7 0

2 years ago