Ask question

Ask question

All categories

2 years ago

12

Jordyn's rectangular garden is represented in the diagram below. If a diagonal walkway crosses their garden, what is its length,

in feet?
Walkway
8 feet
15 feet

1 answer:

agasfer [191]2 years ago

3 0

Answer: 23

Step-by-step explanation:

You might be interested in

Aspirin is sold in boxes of 24 for $3.69, 50 for $5.49, 100 for $8.29, and 150 for $11.99. Which box has the best unit rate.

NNADVOKAT [17]

Answer:

150 for 11.99

the pills in this box are the cheapest

4 0

3 years ago

A baby elephant that is 4 ft tall casts a

Kazeer [188]

Answer:

15 ft

Step-by-step explanation:

10/4

=2.5

6*2.5

=15 ft

PLS GIVE BRAINLIEST

7 0

2 years ago

Read 2 more answers

denis-greek [22]

Answer:

$\frac{3\±\sqrt{3}}{3}$

Step-by-step explanation:

Whe have the function $3x^2-6x+2=0$

To solve this equation we must factor.

To factor, we need to find the points where the function is equal to zero. So we use the quadratic formula

$\frac{-b\±\sqrt{b^2-4ac}}{2a}$

Where:

a = 3

b = -6

c = 2

Then

$\frac{-(-6) + \sqrt{(-6)^2-4(3)(2)}}{2(3)} = \frac{3+\sqrt{3}}{3}\\\\and\\\\\frac{-(-6) - \sqrt{(-6)^2-4(3)(2)}}{2(3)}= \frac{3-\sqrt{3}}{3}$

finally the correct answer is $\frac{3\±\sqrt{3}}{3}$

5 0

2 years ago

Read 2 more answers

What are the rules for rotating a figure about the origin?

Anastaziya [24]

A

Step-by-step explanation:

90 Degree Rotation. When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). ...

180 Degree Rotation. When rotating a point 180 degrees counterclockwise about the origin our point A(x,y) becomes A'(-x,-y). ...

270 Degree Rotation.

6 0

3 years ago

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$

c. The area of the triangle is given by $A = 0.5\times h \times b$ . Differentiating w.r.t t,

$\displatstyle{\frac{dA}{dt} = 0.5 b \frac{dh}{dt} + 0.5 h \frac{db}{dt}}$

Plugging in b = 8, h = 13.856, $\frac{dh}{dt} = -0.588$ ,

$\frac{dA}{dt} = -2.352 + 6.928 = \mathbf{4.576 ft^2/sec}$

8 0

3 years ago