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2 years ago

Consider the system of equations. y = −2x + 4 y = − 1/3x − 1

Mathematics

1 answer:

ipn [44]2 years ago

4 0

Hey there! I'm happy to help!

We have two values for y. Since y=y, this means that −2x + 4 and − 1/3x − 1 are equal as well, so we can put them in an equation and solve for x.

−2x + 4 = − 1/3x − 1

We subtract 4 from both sides.

-2x=-1/3x-5

We add 1/3 x to both sides.

-5/3x=-5

We divide both sides by -1 2/3.

x=3

Now, we plug this into one of the original equations to find y.

y=-2(3)+4

y=-6+4

y=-2

Therefore, the solution is (3,-2) or x=3 and y=-2.

I hope that this helps! Have a wonderful day! :D

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Solution :

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$\: \qquad \dashrightarrow \sf{{ \pi \: \times {(490)}^{2} {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:490 \times 490 \: {m}^{2}}}$

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Area of the inner circle :

$\: \qquad \dashrightarrow \sf{{ \pi \: \times {(210)}^{2} {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:210 \times 210 \: {m}^{2}}}$

$\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{210} \times 210 \: {m}^{2}}}$

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⠀

Therefore,

Area of the region inside the circular paths :

$\: \qquad \dashrightarrow \sf{{ \ (754600 - 138600 ) \: {m}^{2}}}$

$\: \qquad \dashrightarrow \bf{{ \ 616000 \: {m}^{2}}}$

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