Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.
But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;
f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
Answer:
(9/2, 7/2)
Step-by-step explanation:
The easiest way to remember how to do this problem is to average the x-coordinates and average the y-coordinates.
So, in your problem (-3 + 12)/2 = 9/2 and (-5 + 12)/2 = 7/2
The midpoint is (9/2, 7/2)
We want to determine the domain of

any function of the form

is called an "exponential function",
the only condition is that b is positive and different from 1, and a is a nonzero real number.
The domain of such functions is all real numbers.
That is for any x, the expression <span>3(2^-x) "makes sense".
Answer: </span><span>The domain is all real numbers</span>
Answer:
area of the figure: 29.92 m²
formula's:
- area of rectangle: length * width
- area of sector: ∅/360 * πr²
solving steps:
area of rectangle + area of sector
5.5 * 4 + 30/360 * π(5.5)²
22 + 7.919
29.92 m²
Answer:
<JKL=123
Step-by-step explanation:
57+57=114
360-114=246
246/2=123
<JKL=123