I need help with 1-43
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The equation when rewritten is
When we consider the vertex form of the equation:
y= 3(x-2)^2 - (x-5)^2
Expanding further:
2((x-0.5)^2 - 27/4) = 2( (x-0.5)^2)- 27/2
Thus, the final form of the equation would be
Read more about equations here:
#SPJ4
Part 1
Focus on triangle ABC.
Since AB is a diameter of the circle, this means angle ACB is 90 degrees. Refer to Thale's Theorem. Or you could use the inscribed angle theorem. Thale's theorem is a special case of the inscribed angle theorem.
Minor arc CB is 48 degrees. Use the inscribed angle theorem to see that angle CAB is 48/2 = 24 degrees.
Therefore, angle CBA = 90 - (angle CAB) = 90 - 24 = 66 degrees
<h3>Answer: 66</h3>========================================================
Part 2
Inscribed angle CBA was found to be 66 degrees back in part 1.
This doubles to 132 degrees to represent minor arc AC.
Or you could note that:
minor arc AC = 180 - (minor arc CB) = 180 - 48 = 132
Inscribed angle BCD is 48 degrees. This doubles to 96 degrees when using the inscribed angle theorem, and this is the measure of minor arc CBD.
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Here's what we know about the arc measures of the circle
- minor arc AC = 132 degrees
- minor arc CB = 48 degrees
- minor arc BD = 96 degrees
These three arcs, along with minor arc AD, will add up to get a full 360 degree circle. Check out the diagram below.
Adding those 3 pieces gets us 132+48+96 = 276
This means minor arc AD has to be 360 - 276 = 84 degrees
Then use the inscribed angle theorem one more time to divide the minor arc AD in half to get the inscribed angle ACD
84/2 = 42
<h3>Answer: 42</h3>