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3 years ago

Solve the system using the method of your choice: y = 2x – 2

1 answer:

7 0

Y = 2x - 2

x + 3y = 15

I'll do substitution by solving for y:

y = 2x - 2

Solve for y for the second equation:

y = 5 - x/3

Substitute:

2x - 2 = 5 - x/3

Add x/3 to both sides:

7x/3 - 2 = 5

Add 2:

7x/3 = 7

Multiply by 3:

7x = 21

Divide by 7:

x = 3

Substitute x in for one of the original equations:

y = 2(3) - 2

y = 6 - 2

y = 4

The solution set is (3, 4).

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I NEED HELP ON THIS CONSTRUCTED RESPONSE QUESTION! :(

zavuch27 [327]

Answer:

Step-by-step explanation:

She bought 18 ride tickets at $0.75 per ticket, so she spent 18 * $0.75 = $13.50 on rides. She spent a total of $33.50 for only admission and rides.

$33.50 - $13.50 = $20

Admission is $20.

(a) Let y represent total cost. Let x represent the number of ride tickets.

(b) y = 0.75x + 20

x ride tickets cost 0.75x.

Admission is a fixed 20.

Adding the cost of ride tickets, 0.75x, to the admission cost, 20, gives you the total cost, y.

5 0

2 years ago

What is the distance between Harry’s home and his office?

Svetach [21]

Answer:

The distance between Harry’s home and his office? is 15 miles.

Step-by-step explanation:

The speed, distance time formula is:

$Speed(s)=\frac{Distance(d)}{Time(t)}$

Given:

Speed (s) = 30 miles/hour

Then the relation between distance and time is:

$s=\frac{d}{t} \\30=\frac{d}{t}\\d=30t...(i)$

If Speed was 60 miles/hour the time taken is $(t-\frac{1}{4})$ hours.

Then the relation between distance and time is:

$s=\frac{d}{t} \\60=\frac{d}{(t-\frac{1}{4}) }\\d=60t-15...(ii)$

Use the value of d = 30t in (ii)

$d=60t-15\\30t=60t-15\\30t=15\\t=\frac{1}{2} hour$

Determine the distance as follows:

$d=30t\\=30\times\frac{1}{2} \\=15\ miles$

Thus, the distance between Harry’s home and his office? is 15 miles.

5 0

3 years ago

You invested $ 7000 between two accounts paying 3 % and 5 % annual? interest, respectively. If the total interest earned for the

natita [175]

Answer:

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$4,000$ at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

First account

$t=1 years\\ P=\$x\\ r=0.03$

substitute in the formula above

$I=x(0.03*1)$

$I=0.03x$

Second account

$t=1 years\\ P=\$(7,000-x)\\ r=0.05$

substitute in the formula above

$I=(7,000-x)(0.05*1)$

$I=350-0.05x$

Remember that

The interest is equal to $\$290$

Adds the interest of both accounts

$0.03x+350-0.05x=\$290$

$0.05x-0.03x=350-290$

$0.02x=60$

$x=\$3,000$

therefore

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$7,000-\$3,000=\$4,000$ at 5%

7 0

2 years ago

What is the answer some one help please!!

scoray [572]

The correct answer is B

4 0

3 years ago

Help? Multi-Step Equations - Fractions. Solve the Equation. PLEASE DO IT STEP BY STEP (visual)

GREYUIT [131]

R - 10/3 + 1/2 = -11/6...if u multiply everything by the common denominator 6, it will get rid of the fractions.

(6)r - 6(10/3) + 6(1/2) = 6(-11/6)
6r - 60/3 + 6/2 = - 66/6...simplify
6r - 20 + 3 = - 11
6r - 17 = -11
6r = -11 + 17
6r = 6
r = 6/6
r = 1 <===

5 0

3 years ago