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STatiana [176]
3 years ago
11

The two functions below are used to represent the height of a rocket above the ground after it is launched. Which rocket reaches

a greater distance above the ground at its maximum height? Rocket A: y = -6x 2 + 96x Rocket B: y = -4x 2 + 80x Rocket reaches a maximum height that is greater than the maximum height of Rocket

Mathematics
2 answers:
Korvikt [17]3 years ago
7 0

Answer:

  Rocket B reaches a maximum height that is greater than the maximum height of Rocket A.

Step-by-step explanation:

A graph quickly shows the answer to this question.

__

In vertex form, the equation for Rocket A is ...

  y = -6(x² -16x +8²) +6(8²)

  y = -6(x -8)² +384 . . . . . . . . . maximum height is 384 feet

__

The corresponding equation for Rocket B is ...

  y = -4(x² -20x +10²) +4(10²)

  y = -4(x -10)² +400 . . . . . . . . maximum height is 400 feet

Rocket B reaches a maximum height greater than that of Rocket A.

AVprozaik [17]3 years ago
6 0

Rocket B reaches a maximum height that is greater than the maximum height of Rocket A.

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Answer:

a. P(24)=0.00007

b. P(23)=0.00018

c. There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

Step-by-step explanation:

The probabilities of two events ("fire"and "theft") are compared to the probabilities of a certain number of days of rain during July.

The probabilities of "fire"and "theft" are around P=0.0001, and we need to calculate if the probability of exactly 23 and exactly 24 days of rain July have approximately the same probability.

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The parameter then is:

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For 24 days, the probability is:

P(24)=\frac{10^{24}e^{-10}}{24!}=\frac{1*10^{24}*4.54*10^{-5}}{6.20*10^{23}}  = 0.00007

The probability of 23 days of rain is 27% less than P=0.0001.

For 23 days of rain, the probability is:

P(23)=\frac{10^{23}e^{-10}}{23!}=\frac{1*10^{23}*4.54*10^{-5}}{2.59*10^{23}}  = 0.00018

The probability of 23 days of rain is 76% more than P=0.0001.

There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

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