For the first one it’s 40 feet
The second one is 32
The last is 40
The second one is 32
The last is 40
The two functions below are used to represent the height of a rocket above the ground after it is launched. Which rocket reaches
a greater distance above the ground at its maximum height? Rocket A: y = -6x 2 + 96x Rocket B: y = -4x 2 + 80x Rocket reaches a maximum height that is greater than the maximum height of Rocket
2 answers:
Answer:
Rocket B reaches a maximum height that is greater than the maximum height of Rocket A.
Step-by-step explanation:
A graph quickly shows the answer to this question.
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In vertex form, the equation for Rocket A is ...
y = -6(x² -16x +8²) +6(8²)
y = -6(x -8)² +384 . . . . . . . . . maximum height is 384 feet
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The corresponding equation for Rocket B is ...
y = -4(x² -20x +10²) +4(10²)
y = -4(x -10)² +400 . . . . . . . . maximum height is 400 feet
Rocket B reaches a maximum height greater than that of Rocket A.
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Answer:
E. 44 meters
Step-by-step explanation:
The function that models the distance covered by the object is
where s(t) is in meters and t is in seconds.
The distance covered by the object after 1 second is
The distance covered by the object after 1 second is
The distance covered between 1 second and 5 seconds is
50-6=44m