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3 years ago

Sheila either walks to school or cycles, the probability that she walks it 0.65.

1 answer:

5 0

In this question, the probability that Sheila walks is 0.65 and if she walks, which mean the probability to take cycle is 0.35. The probability that shell be late if walking is 0.4 and i<span>f she cycles the probability that shell be late is 0.1

The probability that she will be late:
0.65*0.4 + 0.35*0.1= 0.26+ 0.035= 0.295

</span>The probability that she will not be late:
1-0.295= 0.705= 70.5%

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Need Help ASAP!!.

mihalych1998 [28]

Answer:

Part 1) Greta's right, the triangle is incorrect.

Part 2) $34,203\ ft$

Part 3) The height of the tree is $23.3\ ft$ , Trey’s house is not at risk

Step-by-step explanation:

Part 1) we know that

In the right triangle of the figure

$sin(30\°)=\frac{1}{2}$

$sin(30\°)=\frac{6\sqrt{3}}{12}=\frac{\sqrt{3}}{2}$

Compare

$\frac{1}{2}\neq\frac{\sqrt{3}}{2}$

therefore

The triangle is not correct

Because

The side adjacent to the 30 degree angle should be $6\sqrt{3}$ and the side opposite the 30 degree angle should be $6$

Part 2)

Let

x--------> the distance from the airplane to the SCCA (hypotenuse of the right triangle)

we know that

$sin(17\°)=\frac{10,000}{x}$

$x=\frac{10,000}{sin(17\°)}$

$x=34,203\ ft$

Part 3)

Let

x--------> the height of the tree

we know that

$tan(43\°)=\frac{h}{25}$

$h=tan(43\°)(25)=23.3\ ft$

$23.3\ ft< 25\ ft$

therefore

Trey’s house is not at risk

5 0

4 years ago

OBSERVATION A person standing 100 feet from the bottom of a cliff notices a tower on top of the cliff. The angle of elevation to

vekshin1

Answer:

The tower is 102.26 feet tall.

Step-by-step explanation:

We have drawn the triangle for your reference.

According to the figure point 'A' is the persons eye.

Point 'B' is the bottom of the cliff.

Point 'C' is the top of the cliff.

And Point 'D' is the top of the tower.

Given,

A person standing 100 feet from the bottom of a cliff notices a tower on top of the cliff.

So from diagram we can say that;

Length of AB = 100 ft

The angle of elevation to the top of the cliff is 30°.

So from diagram we can say that;

∠CAB = 30°

the angle of elevation to the top of the tower is 58°.

So from diagram we can say that;

∠DAB = 58°

We have to find the height of the tower i.e. CD.

Solution,

In ΔCAB,

∠CAB = 30°

AB = 100 ft

Now according to trigonometric ratios;

$tan\theta=\frac{opposite\ side}{adjacent\ side}$

Substituting the values we get;

$tan\ 30\° = \frac{BC}{100}$

Now

$tan\ 30\° = \frac{1}{\sqrt{3}}$

$\frac{1}{\sqrt{3}} = \frac{BC}{100}\\\\BC =\frac{100}{\sqrt{3}} = 57.74 \ ft$

In ΔDAB,

∠DAB = 58°

AB = 100 ft

Now according to trigonometric ratios;

$tan\theta=\frac{opposite\ side}{adjacent\ side}$

Substituting the values we get;

$tan\ 58\° = \frac{BD}{100}$

Now

$tan\ 58\° = 1.60$

$1.60 = \frac{BD}{100}\\\\BD =100\times 1.6 = 160 \ ft$

Now BD = BC + CD

CD = BD - BC = 160 - 57.74 = 102.26 ft

Hence The tower is 102.26 feet tall.

6 0

4 years ago

Write the equations of a line through the point (-3,-8) with a slope of -3/5 in

kompoz [17]

y=mx+b is the standard function for any straight line

y and x are constants, so they never change in the final form

m is the slope, which is given

b is the y intercept, which is not given

we have to plug in the values to find the solution, so plug in the (x,y) coordinates for their respective places in the equation

-8 = (-3/5)(-3) + b

-8 = 1.8 + b

-9.8 = b

now that we have b, we can just put the slope back in for m and get the answer

y= -3/5x -9.8

4 0

3 years ago

Simplify each each expression. If not possible, write simplified.

Harman [31]

1. 10x
2. 18g
3. 6m
4. 4p
5. -5y
6. 9w
7. c^2+3d
8. 3a^2+2b^2+6a
9. 3x^2+x
10. 16x-y+3
11. 68x^2-34x-1
12. 32
13. 32
14. -9
15. 3m+3n
16. 6x-6y
17. 15f+5

6 0

4 years ago

Chris can be paid in one of two ways. Plan A is a salary of $490 per month, plus a commission of 9% of sales. Plan B is a sal

Tanya [424]

Step-by-step explanation:

Explanation:

First, when dealing with percents, "Percent" or "%" means "out of 100" or "per 100", Therefore x% can be written as

x/100.

The expression for Plan A can be written as:

490+(9/100)s where s is the sales for the month.

The expression for Plan B can be written as:

826+(3/100)s

The question we are being asked is when is Plan A > Plan B. So, we can write and solve this inequality:

490+(9/100)s>826+(3/100)s

490+(9/100)s−490−(3/100)s>826+(3/100)s−490−(3/100)s

490−490+(9/100)s−(3/100)s>826−490+(3/100)s−(3/100)s

0+(9/100)s−(3/100)s>826−490+0

(9/100)s−(3/100)s>826−490

(9/100−3/100)s>336

(6/100)s>336

(100/6)×(6/100)s>(100/6)×336

s> 33600/6

s>5,600

Plan A is better when sales for the month are greater than $5,600.

8 0

4 years ago