Please help please ASAP
1 answer:
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Answer:
a(n)=1.15[a(n-1)]
Step-by-step explanation:
we know that
Let
a0 -----> the length of the original copy
<em>The first copy is equal to</em>
a1=1.15(a0)
<em>The second copy is </em>
a2=1.15[1.15(a0)] or a2=1.15[a1]
<em>The third copy is</em>
a3=1.15{1.15[1.15(a0)]} or a3=1.15[a2]
therefore
A recursive formula will be
a(n)=1.15[a(n-1)]
Answer:
3.58
Step-by-step explanation:
Given :
y = 2x + 4 -------- eq1
y = 2x - 4 -------- eq2
sanity check : both equations have same slope, so we can conclude that they are both parallel to one another.
Step 1: consider equation 1, pick any random x-value and find they corresponding y-value. we pick x = -2
This gives us y = 2(-2) + 4 = 0
Hence we get a point (x,y) = (-2,0)
Step 2: express equation 2 in general form (i.e Ax + By + C = 0)
y = 2x-4 -------rearrange---> 2x - y -4 = 0
Comparing with the general form, we get A = 2, B = -1, C = -4
Recall that the distance between 2 parallel lines is given by the attached formula (see attached picture).
substituting the values for A, B, C and (x, y) from the previous step:
d = | (2)(-2) + (-1)(0) + (-4) | / √(2² + (-1)²)
d = | -4 + 0 - 4 | / √(4 + 1)
d = | -8 | / √5
d = 8 / √5
d = 3.5777
d = 3.58 (rounded 2 dec. pl)
