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3 years ago

Please help please ASAP

Mathematics

1 answer:

FrozenT [24]3 years ago

4 0

Answer:

PV = 6 and PT = 3

Hope it will help :) see pic ❤

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Somebody help.. im so lost!!

aleksley [76]

What type of math is this?

4 0

3 years ago

HELP ME! Please, I will give brainliest and extra points :) Thank you

Arte-miy333 [17]

Answer:

solution set of f(x) = g(x) is x∈{0,1}

Step-by-step explanation:

For all exponential functions b^x,

b^0 is always 1, and b^1 is always b.

f(x) = -3/4 x + 2

g(x) = (1/4)^x + 1

g(0) = 2, f(0) = 2

g(1) = 5/4, f(1) = 5/4

7 0

3 years ago

Given sin(−θ)= −1/4 and tanθ= 15√15 . What is the value of cosθ ?

dangina [55]

$\sin = \frac{y}{r} \\ \\ \tan = \frac{y}{x} \\ \\ \cos = \frac{x}{r} \\ \\ {x}^{2} + {y}^{2} = {r}^{2}$

$- \sin = \frac{ - 1 \: = \: y}{4 \: = \: r}$
$15 \sqrt{15} = \frac{1}{x} \\ \\ x = .017$
$\cos = \frac{.017}{4} = .0043$

4 0

3 years ago

Took a photo to use

ruslelena [56]

Answer:

x=9

<A=23

<B= 69

Step-by-step explanation:

1. 2x+5+3(2x+5)=92 2. 2x+5+6x+15=92 3. 8x+20=92 4. 8x=72 5. x=9

<A= 2(9)+5=18+5=23

<B= 3(2(9)+5)=3(23)=69

5 0

2 years ago

Please help me please will give brainliest to anyone only do number 11

AnnZ [28]

9514 1404 393

Answer:

9. ±1, ±2, ±3, ±6

11. ±1, ±2, ±3, ±4, ±6, ±12

Step-by-step explanation:

The possible rational roots are (plus or minus) the divisors of the constant term, divided by the divisors of the leading coefficient.

Here, the leading coefficient is 1 in each case, so the possible rational roots are plus or minus a divisor of the constant term.

9. The constant is -6. Divisors of 6 are 1, 2, 3, 6. The possible rational roots are ...

±{1, 2, 3, 6}

11. The constant is 12. Divisors of 12 are 1, 2, 3, 4, 6, 12. The possible rational roots are ...

±{1, 2, 3, 4, 6, 12}

_____

A graphing calculator is useful for seeing if any of these values actually are roots of the equation. (The 4th-degree equation will have 2 complex roots.)

8 0

3 years ago