Ask question

Ask question

All categories

4 years ago

13

Stefan plant seeds for 30 carrot plants and 45 beat plants in five rows with the same number of seeds in each row. How many seed

s are planted in each row

1 answer:

bixtya [17]4 years ago

6 0

The answer is 15 seeds per row

You might be interested in

a cubiod of demension 56 * 49 * 29 how many small cubes with sides 7cm can be placed in the given cubiod

malfutka [58]

Answer:

232

Step-by-step explanation:

n *volume of cube = volume of cuboid

n*7*7*7=56*49*29

n=232

3 0

3 years ago

Help please ill give brainliest

nadezda [96]

Answer:

I'm pretty sure triangle 6 is similar to triangle 1

Step-by-step explanation:

7 0

3 years ago

A circle with center c(4,-2) contains the point D( 8,1). What is the equation of the line perpendicular to the radius of the cir

Nady [450]

Answer:

4x +3y = 10

Step-by-step explanation:

The radius CD has slope Δy/Δx = (1-(-2))/(8-4) = 3/4.

The equation for the perpendicular line through point C(4, -2) can be written as ...

Δx(x -4) +Δy(y -(-2)) = 0

4(x -4) +3(y +2) = 0

4x +3y -10 = 0 . . . . . . general form equation for the line

4x +3y = 10 . . . . . . . . .standard form equation for the line

8 0

3 years ago

Y=2x+0.5 I have to solve this using a weird table and then I have to graph it. How?

g100num [7]

You have to choose any input ,plug it in the equation ,solve it and look what is the output.Do that for the rest of the points . when you finish graph your points.

5 0

4 years ago

Use simpson's rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. compare y

Lubov Fominskaja [6]

y = ln x , 1 <= x <= 3, about x axis and n = 10, dy/dx = 1/ x

S = (b a) ∫ 2π y √( 1 + (dy/dx) ^2) dx

so our f(x) is 2π y √( 1 + (dy/dx) ^2)

(b - a) / n = / 3 = (3-1) / 30 = 1/15

x0 = 1 , x1 = 1.2, x2 = 1.4, x3 = 1.6 ....... x(10) = 3

So we have , using Simpsons rule:-

S10 = (1/15) ( f(x0) + 4 f(x1) + 2 f)x2) +.... + f(x10) )

= (1/15) f(1) + f(3) + 4(f(1.2) + f(1.6) + f(2) + f(2.4) + f(2.8)) + 2(f(1.4) + f(1.8) + f(2.2) + f(2.6) )

( Note f(1) = 2 * π * ln 1 * √(1 + (1/1)^2) = 0 and f(3) = 2π ln3√(1+(1/3^2) = 7,276)

so we have S(10)

= 1/15 ( 0 + 7.2761738 + 4(1.4911851 +

5 0

4 years ago