Answer:
B. i and iii
Step-by-step explanation:
There are mistakes in your question. But I solve this problem using the average mean of 15 because that is what is contained in the solution
Hypothesis
H0: u <= 15
H1: u > 15
Mean of x = 16.6
S = 2.22
Test statistic used is t test
16.6 - 15 / 2.22/√24
= 3.531
We find the critical value
Degree of freedom = 24-1 = 23
This is a one tailed test
Critical value = 1.714
We find p value using Ms excel T distribution function
= 0.000894
To make the decision
3.531 > 1.714 so we conclude that
I.) Reject null hypothesis
Iii) conclude an average if more than 15 hours is volunteered per month. So no need to institute the program.
The answer option Is B
Answer:
the value of the investment after 3 years= £11,904
Step-by-step explanation:
sarah invests £9600 at a simple interest rate of 8% per year
number of years = 3
Formula for simple interest
I = P*n* r
P is the initial amount invested= 9600
r is the rate of interest = 8% = 0.08
n = number of years = 3
Now we find interest using formula
I = 9600 * 0.08 * 3= 2304
Interest amount is 2,304
Now we add the interest with the initial amount to get the value of investment after 3 years
9600 + 2304= 11904
Total interest= principal*interest rate*time
I=500×0.023×4
I=46
It take 2.75 years
Step by step explanation:
18600$ / 1000$x6.75%=2.75
Answer:
14.99 hours
Step-by-step explanation:
The formula for half-life is given as,
R/R' = 2ᵃ/ᵇ...................... Equation 1
Where R= Original mass of sodium-24, R' = mass of Sodium-24 after disintegration, a = Total time taken for sodium-24 to disintegrate, b = half-life of sodiun-24.
Given: R = 1 kg, R' = 0.0156 kg, a = 90 hours
Substitute into equation 1 and solve for b
1/(0.0156) = 2⁹⁰/ᵇ
Taking the log of both side
log[1/(0.0156)] = log(2⁹⁰/ᵇ)
log[1/(0.0156)] = 90/b(log2)
90/b = log[1/(0.0156)]/log2
90/b = 6.0023
b = 90/6.0023
b = 14.99 hours
b = 14.99 hours.
Hence the half-life of Sodium-24 is 14.99 hours
