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3 years ago

How you can use the distributive property to solve multistep equations

Mathematics

1 answer:

NISA [10]3 years ago

6 0

Answer:

You can distribute and then simplify

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What is the answer how did you get the answer

bulgar [2K]

The artist will need 24 tan tiles. This is because 16 divided by 2 is 8, and 3 times 8 is 24.

8 0

3 years ago

Read 2 more answers

15 points if you complete it <3

liberstina [14]

Answer:

3:0.5, 9:1.5, 6:1, 33: 5.5, 12:2, 39:6.5, 15:25.

the unit rate of eggs per 1 kg of flour = 6 eggs/1 kg of flour

Step-by-step explanation:

Usually tables go in ascending numerical order...the numbers only go up, reading from right to left. But the math for this has the numbers kind of jumping around.

3/0.5 = 9/x, then cross-multiply,

3x = 9(0.5)

3x = 4.5 then divide by 3

x = 1.5

--------------------------

3/0.5 = x/1

3 = 0.5x

6 = x

----------------------------

If you need me to keep showing the math for the rest of the table, let me know.

3 0

3 years ago

2*log(y+5)=log 20-log 5

Ilia_Sergeevich [38]

Answer:

$y = - 3$

Step-by-step explanation:

$\frac{2 log_{10}(y + 5) }{2} = \frac{ log_{10}(20) }{2} - \frac{ log_{10}(5) }{2}$

$log_{10}(y + 5) = \frac{ log_{10}(20) }{2} - \frac{ log_{10}(5) }{2}$

$y + 5 = 2 \\ y = - 3$

7 0

3 years ago

Can you fill in the blanks. Thx

maria [59]

Answer:

Answer is below

Step-by-step explanation:

Download docx

4 0

3 years ago

4. Automobile policies are separated into two groups: low-risk and high-risk. Actuary Rahul examines low-risk policies, continui

ANTONII [103]

Answer:

Step-by-step explanation:

for n ∈ N

Since Actuary Rahul examines low-risk policies, continuing until a policy with a claim is found and then stopping.

∴ the probability that Actuary Rahul examines exactly n policies

$(0.9)^{n-1}.(0.1)---(1)$

the probability that Actuary Toby examines more than exactly n policies

$(0.8)^n---(2)$

Given that policies are actually independent

∴ the probability that the event (1) and (2) happens simultaneously is

$(0.9)^{n-1}*(0.1)*(0.8)^n$

∴ the probability that Actuary Rahul examines fewer policies than Actuary Toby

$\sum ^\infty _{n=1} (0.9)^{n-1}*(0.1)*(0.8)^n\\\\=(\frac{0.1}{0.9} \sum ^\infty _{n=1}(0.72)^n\\\\=\frac{1}{9} (\frac{0.72}{0.28} )\\\\=\frac{2}{7} \\\\=0.2857$

<h3>the probability that Actuary Rahul examines fewer policies than Actuary Toby is 0.2857</h3>

5 0

3 years ago