Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Patrick has a total of 600 meters skein of yarn.
He used 248.9 meters of yarn to make a hat.
Now, If he has used 248.9 meters of yarn, we need to find how much yarn has he left.
We need to subtract the amount of yarn used from the total length. That is, 248.9 from 600.

So, now Patrick has left 351.1 meters of yarn.
Patrick needs to make a scarf that needs 354.03 meters of yarn but after making a hat he has left with only 351.1 meters of yarn. Therefore, Patrick does not have enough yarn to make a scarf.
That's what it will look like
The answer is 58 I think 166-8= 158