We can write this as the difference of squares:
(5b⁸+8c)(5b⁸-8c)
To write as the difference of squares, take the square root of each term first:
√25b¹⁶ = 5b⁸; √64c² = 8c
Now we write this as a sum in one binomial and a difference in the other:
(5b⁸+8c)(5b⁸-8c)
Answer:
formula for ratio: you can write a ratio with :, or, /
x axis is horizontal
0= x axis 6= y axis
Step-by-step explanation:
![\bf \begin{cases} f(x)=\cfrac{2}{x}\\[1em] g(x)=x^2+9 \end{cases}~\hspace{5em}f(~~g(x)~~)=\cfrac{2}{g(x)}\implies f(~~g(x)~~)=\cfrac{2}{x^2+9}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20f%28x%29%3D%5Ccfrac%7B2%7D%7Bx%7D%5C%5C%5B1em%5D%20g%28x%29%3Dx%5E2%2B9%20%5Cend%7Bcases%7D~%5Chspace%7B5em%7Df%28~~g%28x%29~~%29%3D%5Ccfrac%7B2%7D%7Bg%28x%29%7D%5Cimplies%20f%28~~g%28x%29~~%29%3D%5Ccfrac%7B2%7D%7Bx%5E2%2B9%7D)
that's one combination for f(x) and g(x), off many combinations.
The answer would be 1/2y > 22
Answer:
35:
30 (tens) 5 (ones)
16:
10 (tens) 6 (ones)
Step-by-step explanation:
Add the tens:
30+10 =40
Add the ones:
5+6=11
Add the final answer for the tens and ones together:
40+11=51
I hope this helps! Lemme know in the comments if this made sense to you?
