The equation of a circle exists:
, where (h, k) be the center.
The center of the circle exists at (16, 30).
<h3>What is the equation of a circle?</h3>
Let, the equation of a circle exists:
, where (h, k) be the center.
We rewrite the equation and set them equal :
We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.
-2hx = -32x
h = -32/-2
⇒ h = 16.
-2ky = -60y
k = -60/-2
⇒ k = 30.
The center of the circle exists at (16, 30).
To learn more about center of the circle refer to:
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It's a simultaneous equation:
Steps:
1.Number the equations..
a+b=77 -1
a-b=13 -2
2. Choose what variable you want to use. In this case I would use the "b". Since the signs in front of the "b's" are different, add the two equations together
a + b = 77
+ + +
a (-b) = 13
Which gives;
2a = 90
Then solve to find a:
2a=90
a= 90/2
a=45
3.Then plug the "a" value into any of the original equations to find the "b" value. I would use equation 1 since the all the variables are positive.
a + b = 77
(45) + b = 77
b=77-45
b=32
4.Solution
a=45
b=32
Don't understand this either
The answer is 100 bc u got to put it into a proportion
Hello,
Question:
Keisha solved the following equation:
4x − 2x + 8 = 6(x + 4)
Which step has an incorrect justification? (Make sure to type only the number of the step into the blank: 1, 2, 3, 4 or 5)
Correct Solution:
x − 2x + 8 = 6(x + 4)
4x + −2x + 8 = (6) (x) + (6) (4) (Distribute)
4x + −2x + 8 = 6x + 24
(4x + −2x) + (8) = 6x + 24 (Combine Like Terms)
2x + 8 = 6x + 24
2x + 8 = 6x + 24
Subtract 6x from both sides.
2x + 8 − 6x = 6x + 24 − 6x
−4x + 8 = 24
Subtract 8 from both sides.
−4x + 8 − 8 = 24 − 8
−4x = 16
-4 x -4 = 16
x = -4
Answer:
Where keisha went wrong was forgeting to subtract 6x to both sides.
Incorrrect step is #3
