Answer:
f(x) has a slope of -1 and has a range of all real numbers.
Step-by-step explanation:
A linear function is a continuous function, so that exist a range value for all value of the domain, which corresponds to all real numbers. Regarding the function described above, the y- and x-intercepts are, respectively:
x-Intercept


f(x) has a x-intercept of (-24,0).
y-Intercept


f(x) has a y-intercept of (0, -24).
Lastly, the linear function has a slope of -1.
Answer:
<em>The circle has a radius of 41 inches</em>
Step-by-step explanation:
<u>Circles</u>
There are certain relations in a circle that help us to identify and calculate some of its characteristics.
The figure shows a circle with three parameters which will lead us to determine its radius. First, we have a chord that measures 80 inches. Since it doesn't go through the center of the circle, it's not the diameter.
But we also have the distance from the center to the chord, making a right angle with it. This makes the chord be divided into two equal parts of 40 inches each.
Now we form a right triangle joining the center to one of the extremes of the chord. The hypotenuse of this triangle is the required radius of the circle. Like every right triangle, this must comply with Pithagora's theorem:

where r is the hypotenuse and x, y are the legs or the smaller sides of the triangle. We have determined that x=9, y=40 (or vice-versa, it doesn't matter). Therefore

Solving for r

The circle has a radius of 41 inches
Answer:
The answer is 9(7x – 1).
Step-by-step explanation:
63x – 9
3 × 3 × 7 × x – 3 × 3
9(7x – 1)
Thus, The answer is 9(7x – 1).
<u>-TheUnknownScientist</u><u> 72</u>
It’s been awhile since I’ve done a problem like this but I believe it’s solved as below:
The area of a circle is equal to πr2. That will tell you the entire area of the circle. Then you would need to divide that by 2 to get the area of the 180° arc.
So, the area of this circle is 153.94 square meters. If you divide that by 2 (since 180° is half of a circle) you would get 76.97 square meters.