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Reil [10]
3 years ago
7

An employee is angry with his boss and wants to sabotage the company. To accomplish this he secretly changes some of the values

in his boss's copy of the quarterly report. His boss then reads this false data and makes decisions based on this fraudulent information. In this instance, what quality of information security has been damaged?a. Availability loss
b. Confidentiality loss
c. Integrity loss
d. Access loss
Computers and Technology
1 answer:
bonufazy [111]3 years ago
7 0

Answer: Integrity loss

Explanation:

A set of data is said to have experienced a Loss of Integrity if some event has caused it to be incorrectly altered

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Using the Sakila database, create a query that displays the film title, description, as well the actor first and last name for a
Alex787 [66]

Answer:

Select title, description , first_name, last_name from film inner join film_actor on film.film_id = film_actor.film_id inner join actor on film_actor.actor_id = actor.actor_id where title LIKE 'zo%';

Explanation:

  • The INNER JOIN keyword selects records that have matching values in both tables.
  • The WHERE clause is used to filter records.
  • The WHERE clause is used to extract only those records that fulfill a specified condition.
7 0
3 years ago
Write a program to display MPH (Miles per Hour). Create a function to calculate the MPH. Ask the user for the number of miles dr
puteri [66]

Answer:

In Python:

def MPH(miles,minutes):

   mph = round(60 * miles/minutes,1)

   return mph

   

miles = float(input("Miles: "))

minutes = float(input("Minutes: "))

if miles>0 and minutes>0:

   print("MPH: ",MPH(miles,minutes))

else:

   print("Positive inputs only")

Explanation:

This defines the function

def MPH(miles,minutes):

This calculates mph rounded to 1 decimal place

   mph = round(60 * miles/minutes,1)

This returns the calculated mph

   return mph

The main begins here

This gets input for miles    

miles = float(input("Miles: "))

This gets input for minutes

minutes = float(input("Minutes: "))

If miles and minutes are positive

if miles>0 and minutes>0:

This calls the MPH function

   print("MPH: ",MPH(miles,minutes))

If otherwise, this prompts the user for positive inputs

<em>else:</em>

<em>    print("Positive inputs only")</em>

7 0
3 years ago
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
Which types of attacks are thwarted by complex passwords that are combinations of upper and lower case letters, numbers, and spe
lesantik [10]

The types of attacks that are known to be thwarted by complex passwords that are combinations of upper and lower case letters, numbers, and special characters are said to be Brute Force Attacks.

What is Brute Force Attacks?

This is known to be an attack that is said to be a very  crude type of attack and it is often seen as a brute-force attack.

Note that is one that does not depend on lists of passwords, but it is one that often tries all the  very possible combinations of permitted character types.

Hence, this type of attack was known to be historically seen as ineffective, and it is said to be The types of attacks that are known to be thwarted by complex passwords that are combinations of upper and lower case letters, numbers, and special characters are said to be Brute Force Attacks.

Learn more about Brute Force Attacks from

brainly.com/question/17277433

#SPJ1

3 0
2 years ago
What is the advantages and disadvantages of hardware devices and software devices ?
yulyashka [42]

Answer:

Advantages of hardware:

Physical existence

Multitasking

Speedy

Disadvantages:

Costly as different equipment cost differently

Time consuming

requires space

Privacy issues

Explanation:

Advantages of Software:

Less costly

Improved privacy controls

Requires no space

Disadvantages:

Does not have physical existence

hacking and cyber attacks may steal important information

Regular updates required

3 0
3 years ago
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