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Aneli [31]
3 years ago
14

Use the STL class vector to write a C function that returns true if there are two elements of the vector for which their product

is odd, and returns false otherwise. Provide a formula on the number of scalar multiplications in terms of n, the size of the vector, to solve the problem in the best and worst cases. Describe the situations of getting the best and worst cases, give the samples of the input at each case and check if your formula works. What is the classification of the algorithm in the best and worst cases in terms of the Big-O notation

Computers and Technology
1 answer:
Tema [17]3 years ago
7 0

Answer:

Code is provided in the attachment form

Explanation:

Vector Multiplication code:

Vector_multiplication.c file contains C code.

See attachment no 1 attached below

Classification of Algorithm: For creating elements in vector c of size n, number of scalar  multiplications is equal to n. The size of original two vectors scales directly with the number of  operations. Hence, it is classified as O(n).

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Write a procedural programming loop.. Your loop should start variable n with a value of 10 and count down to zero. The loop shou
anastassius [24]

Answer:

//Here is the for loop in C.

for(n=10;n>0;n--)

{

   printf("count =%d \n",n);

}

Explanation:

Since C is a procedural programming language.Here if a loop that starts with n=10; It will run till n becomes 0. When n reaches to 0 then loop terminates otherwise it  print the count of n.

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{  // variables

int n;

// for loop that runs 10 times

// when n==0 then loop terminates

for(n=10;n>0;n--)

{

   cout<<"count ="<<n<<endl;

}

return 0;

}

Output:

count =10

count =9

count =8

count =7

count =6

count =5

count =4

count =3

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3 0
4 years ago
Write a C++ function with the following signature: void readAndConvert() The function takes no parameters and returns no value.
shepuryov [24]

Answer:

The function is as follows:

void readAndConvert(){

   int n; string symbol,name;

   cin>>n;

   cin>>symbol;

   cin.ignore();

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   vector<string> trades;

   string trade;

   for (int inps = 0; inps < n; inps++){

       getline (cin,trade);

       trades.push_back(trade);}

   

   cout<<name<<" ("<<symbol<<")"<<endl;

   for (int itr = 0; itr < n; itr++){

       string splittrade[3];        int k = 0;

       for(int j=0;j<trades.at(itr).length();j++){

           splittrade[k] += trades.at(itr)[j];

           if(trades.at(itr)[j] == ' '){

               k++;    }}

cout<<splittrade[2]<<": "<<floor(stod(splittrade[1]) * stod(splittrade[0]))<<endl;        }

   }

Explanation:

See attachment for complete program where comments are used to explain each line

Download cpp
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Answer:

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Explanation:

6 0
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user100 [1]
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Answer:

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