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o-na [289]
3 years ago
10

3.305 + 1.7 what's the sum? Also more questions are coming just doing a test

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

  3.305

 +1.7

  5.005

Line up the decimal points and add like you usually would add.

5.005 is the answer.

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Suppose that W1 is a random variable with mean μ and variance σ21 and W2 is a random variable with mean μ and variance σ2. From
vivado [14]

Answer:

Step-by-step explanation:

The concept of variance in random variable is applied in solving for the value of c for the estimator cW1 + (1 − c)W2 to be most efficient. Appropriate differentiation of the estimator with respect to c will give the value of c when the result is at minimum.

The detailed analysis and step by step approach is as shown in the attachment.

7 0
3 years ago
Help pls so people say it’s none of these but idk I am confused.
crimeas [40]

Answer:

Volume = \pi r^2 h

2512 = 3.14 × r^2 × 8

r^2 = \displaystyle\frac{314}{3.14}

r^2 = 100

r = 10 \ cm

Diameter = 2r = 20 \ cm

Dont get confused try to understand : )

8 0
3 years ago
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Please solve 6-12.<br> Picture below.
allochka39001 [22]
The answer for this is 6
5 0
2 years ago
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The midpoint of AB‾AB is M(−4,−3)M(−4,−3). If the coordinates of A are (−1,-2)(−1,−2), what are the coordinates of B?
jonny [76]

Answer:

(-7, -4)

Step-by-step explanation:

The midpoint formula is expressed as;

M (X,Y) = {(x1+x2/2), (y1+y2)/2}

Given that M(-4, -3) and (x1, x2) = (-1, -2)

X = x1+x2/2

-4 = -1+x2/2

-8 = -1 + x2

x2 = -8 + 1

x2 = -7

SImilarly;

Y = y1+y2/2

-3 = -2+y2/2

-3*2 = -2+y2

-6 = -2 + y2

y2 = -6 + 2

y2 = -4

Hence the coordinate of B is (-7, -4)

6 0
3 years ago
Find all solutions in the interval [0,2pi).<br><br> cos 2x + sqrt(2) sinx=1
kykrilka [37]
<span>cos 2x + sqrt(2) sinx=1
</span><span>
Note that: cos 2x = cos^2x - sin^2x = (1-sin^2x) - sin^2x = 1 - 2sin^2x.
So, when alternatively written, you have the following equation:

</span>- 2sin^2x + sqrt(2)sinx + 1 = 1
- 2sin^2x + sqrt(2)sinx = 0

Then, let z=sin(x). So you get,

- 2z^2 + sqrt(2)z = 0
z(- 2z + sqrt(2)) = 0

Either z=0, or - 2z + sqrt(2) = 0 --->  z=sqrt(2)/2.
Then, since z=0 or z=sqrt(2)/2, therefore sin(x)=0, or sin(x)=sqrt(2)/2.

Then, for you remains just to list the angles. (Let me know if this is not fair or if you got questions.)
6 0
3 years ago
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