Answer:
1.(1,5) and (2,6) , 6-5/2-1=1/1 m=1 ,y=1x+b
5=1(1)+b 4=b
y=x+4
2.(1,1) and (3,-8) -8-1/3-1=-9/2 m=-9/2 ,y=-9/2x+b
1=-9/2(1)+b b=11/2
y=-9/x+11/2
3.(2.-3) and (5,-2) m=1/3 ,y=1/3x+b
-3=1/3(2)+b -3=2/3+b
-3-2/3=b
b=-11/3
y=1/3x-11/3
4.(2,5)and (4,3) m=-1 y=-1x+b
5=-1(2)+b 5=-2+b
5+2=b
b=7
y=-1x+7
6.(-3,-5) and (-1,-3) m=2/2=1 y=1x+b
-5=1(-3)+b -5=-3+b
-5+3=b
-2=b
y=1x-2
Step-by-step explanation:
Answer: Choice C) -1/3
The given line has a slope of -1/3 so anything parallel to that given line is also going to have an equal slope (of -1/3)
To find the slope of that line shown, notice how we drop down 1 unit and the move to the right 3 units when we go from the left point to the right point. Alternatively, you can use the slope formula m = (y2-y1)/(x2-x1) to get the same result.
Tangent = opposite / adjacent
In the diagram:
TQ is the short leg or the opposite
QR is the long leg or the adjacent
TR is the hypotenuse. TS is part of the hypotenuse.
Tan(QTR) = TQ / QR
TS = 1 ; TQ = TS so, TQ = 1
Tan(QTR) = 1/QR
I think the answer is C.RQ
Answer:
the answer is 12
Step-by-step explanation:
Simplify both sides of the equation.
12(b−10)+2b=25
(12)(b)+(12)(−10)+2b=25(Distribute)
12b+−5+2b=25
(12b+2b)+(−5)=25 (Combine Like Terms)
52b+−5=25
52b−5=25
add 5 to both sides.
52b−5+5=25+5
52b=30
multiply both sides by 2/5.
(25)*(52b)=(25)*(30)
b=12
A.Determine whether –(x3 + 5x + 1) is equivalent to x3 + 5x + 1. b.Determine whether (–x)3 + 5(–x) + 1 is equivalent to x3 + 5x + 1.
c. Determine whether –x3 + 5x + 1 is equivalent to –(x3 + 5x + 1).
d. Determine whether (–x)3 + 5(–x) + 1 is equivalent to –(x3 + 5x + 1)
A function is even if f(x) = f(-x) for all x.
f(-x) = -x³ + 5(-x) + 1
f(-x) = -x³ - 5x + 1
b.Determine whether (–x)3 + 5(–x) + 1 is equivalent to x3 + 5x + 1.
