Answer: C. 24 units
Step-by-step explanation:
The circumference of a circle is 2πr. Let's say x = 1/3r. Thus, the area of circle A relative to circle B is 1:3. Thus, circle B is 3 times larger than circle A. So, simply divide 64π by 4 to get 16π. Then multiply 16π*3=48π. For the circumference of a circle to be 48, the radius would have to be 24.
Hope it helps <3
Using a linear function, it is found that the product rs is rs = 81.
<h3>What is a linear function?</h3>
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
In this problem, when x changes by 68(from -64 to 68), y changes by -16(from 12 to -4), hence the slope is given by:
m = -16/64 = -0.25.
Hence:
y = -0.25x + b.
When x = 34, y = -4, hence this is used to find b.
-4 = -0.25(34) + b
b = 4.5.
Hence the function is:
y = -0.25x + 4.5.
f(r) = 0, hence:
-0.25x + 4.5 = 0
x = 4.5/0.25
x = 18
r = 18.
f (0) = s, hence s = 4.5.
Then the value of the product is:
rs = 18 x 4.5 = 81.
More can be learned about linear functions at brainly.com/question/24808124
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First, you need to convert 5 1/4 feet to inches. 5.25 x 12 = 63 inches. The ratio of the height of the model to the height of the actual statue in simplest form is 1/42. I don't know if this is correct but I hope this helps you in any way.
Answer:
The correct option is C. 14 ft
Step-by-step explanation:
To calculate the height, we will follow the steps below;
Formula is given to be: h = 2A / b1 +b2
where h = height of the trapezoid b1 and b2 are the bases of the trapezoid and A is the area of the trapezoid
From the question given;
Area A =329 feet² b1 = 30 feet b2 =17 feet
We can now proceed to insert the values into the formula
h = 2A / b1 +b2
h= 2(329) / 30 + 17
h = 658 /47
h=14 feet
Answer:
Persian, Maine Coon, American Shorthair
13.07, 13.6, 13.65
Step-by-step explanation:
I hope this helped!
