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3 years ago

What is the cube root of 12? I have to show my work using common core.

1 answer:

6 0

Analyze perfect cubes:

1^3 = 1
2^3 = 8
3^3 = 27

Since 12 is between 8 and 27, cube root of 12 is between 2 and 3.
You also know it is much closer to 2, since 12 is much closer to 8.

A good guess would be 2.25

(2.25)^3 = 11.39

This is close but slightly less than 12.

When you use your calculator you should get 2.2894.

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Pls help me high paying reward.

Serggg [28]

-3 so top person is correct:)))))

5 0

2 years ago

The graph of 15x + 7y = 15 is shown on the grid. Which ordered pair is in the solution set of 15x + 7y ≥ 15?

elena55 [62]

Answer:

The correct option is c.

Step-by-step explanation:

The given equation is

$15x+7y=15$

The given inequality is

$15x+7y\geq 15$

A point will contained in solution set if the above inequality satisfied by that point.

Check the point (0,-3),

$15(0)+7(-3)\geq 15$

$-21\geq 15$

This statement is false, therefore option a is incorrect.

Check the point (-3,0),

$15(-3)+7(0)\geq 15$

$-45\geq 15$

This statement is false, therefore option b is incorrect.

Check the point (3,3),

$15(3)+7(3)\geq 15$

$66\geq 15$

This statement is true, therefore option c is correct.

Check the point (-3,-3),

$15(-3)+7(-3)\geq 15$

$-66\geq 15$

This statement is false, therefore option d is incorrect.

7 0

3 years ago

#2 Find the value of x. Round to the nearest degree.

Sergio [31]

Answer:

49°

Step-by-step explanation:

arccos x = 15/23

4 0

2 years ago

A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng

tangare [24]

Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, $xy \leq 8000$

So, $x(220-x) \leq 8000$

$220x-x^2 \leq 8000$

So, $220x-x^2 = 8000\\-x^2+220x-8000=0$

General quadratic equation : $ax^2+bx+c=0$

Formula : $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031$

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0

3 years ago

You will have 27 points if you can help me with this please!!!!

KatRina [158]

Answer:1: P 2: d 3:a

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers