m∠1=31
m∠2=59
m∠3=90
m∠4=31
m∠5=90
hope this helps brainliest please!
Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer:67.5294117647
Step-by-step explanation: Or 67.5
Answer:
Step-by-step explanation:
We have the function 
and we have the function 
. We want to find g(x) composed with f(x)
Then, the function (f o g)(x) is the same since f(g(x))
That is, you must do x = g(x) and then enter g(x) into the function f(x).
Simplifying, we obtain:
Finally. The composite function is:
8z=4(2z+1)
First you would distribute the constant into the numbers in the parentheses. so
8z=8z+4
then you would combine like terms which in this case would result in a zero.
8z-8z=0 So the z would be zero or no solution.
