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Paraphin [41]
4 years ago
15

Please can someone show me how to do this. Thanks

Mathematics
1 answer:
Nadusha1986 [10]4 years ago
5 0

Answer:

x equals 3.00cm

Step-by-step explanation:

Use Pythagoras' Theorem.

a = (14x-45)

b = (16x+27)

c = (25x)

Plug in the variables above into Pythagoras' Theorem that is, a^2+b^2=c^2.

Solve the resulting quadratic equation and reject the negative answer as length is always positive.

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Write an equation of the parabola in vertex form that passes through (0, −24) and has vertex (−6, −12)
Elenna [48]
The general equation is y-k=a(x-h)² where (h,k) is the vertex.

So in this case we have y+12=a(x+6)².

Plug in x=0, y=-24: -12=36a, and a=-⅓. Therefore y+12=-⅓(x+6)².
4 0
3 years ago
which is the equation in the slope intercept form for the line that passes through (-1,5) and is parallel to 3x+2y=4?
frozen [14]

Answerr:7

Step-by-step explanation:

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3 years ago
The temperature was 8°F. It dropped so that the temperature was 0°F.
jeka57 [31]

Answer:

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Step-by-step explanation:

6 0
3 years ago
A planet follows an elliptical path described by 16 x squared + 4 y squared = 64. A comet follows the parabolic path y equals x
saul85 [17]

Answer:

The comet might intersect the orbiting planet at (0, -4),(\pm\frac{\sqrt{31}}{2},\frac{15}{4}).

Step-by-step explanation:

Given that, a planet follows an elliptical path described by

16x^2+4y^2=64 .........(1)

A comet follows the parabolic path

y=x^2-4

x^2=y+4.........(2)

To find the intersecting point, we need to solve the above equations.

Putting  x^2=y+4  in the equation (1)

y+4+4y^2=64

\Rightarrow 4y^2+y+4-64=0

\Rightarrow 4y^2+y-60=0

\Rightarrow 4y^2+16y-15y-60=0

\Rightarrow 4y(y+4)-15(y+4)=0

\Rightarrow(y+4)(4y-15)=0

\Rightarrow y=-4, \frac{15}{4}

When y = -4 , then x^2=-4+4 \Rightarrow x=0

When y=\frac{15}{4}, then x^2=\frac{15}{4}+4 \Rightarrow x=\pm \frac{\sqrt{31}}{2}

The comet might intersect the orbiting planet at (0, -4),(\pm\frac{\sqrt{31}}{2},\frac{15}{4}).

5 0
3 years ago
If the angle of elevation of the sun is 63° and the flagpole casts 27-foot shadow, how tall is the flagpole?
VLD [36.1K]

Answer:

Step-by-step explanation:

To help you solve

Use the fact that (height of flagpole)/(length of shadow) = tan(angle of elevation).

5 0
2 years ago
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