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tresset_1 [31]
2 years ago
5

Grogg typed the following $1000$ expressions into his calculator, one by one: \[\sqrt{1}, \sqrt{2}, \sqrt{3}, \sqrt{4}, \dots, \

sqrt{999}, \sqrt{1000}. \]how many times will grogg's result be an integer?
Mathematics
1 answer:
Vanyuwa [196]2 years ago
8 0

Since 30² = 900 and 40² = 1600, between 30 and 40 of the numbers Grogg enters will reduce to integers. Now just find which count is correct. We don't have to look far:

31² = 961

32² = 1024

so there 31 of the outputs of √1, √2, √3, ..., √1000 are integers.

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Answer:

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Step-by-step explanation:

First, you would have to distribute the 3x to everything in the parentheses. So you can write it out as (3x*x^2)+(3x*4x)+(3x*5). Solving this will give you the answer. We'll start off with (3x*x^2). Because we are MULTIPLYING, this part will equal to 3x^3. There is ONE x with 3x (think of it as 3x^1) and 2 x's in x^2, having a total of 3 x's, or x^3. Since the 3 is being multiplied as well, we can write it as 3x^3.

Second, we will solve (3x*4x). We are multiplying, so first we multiply 3*4 and then x*x. 3*4 is 12 and x*x is x^2.  There are 2 x's being mutipled by each other, so the x becomes squared. Now we finish and multiply 12*x^2 wich is 12x^2.

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3 0
3 years ago
How to work out the equation
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first, distribute -6 to (2b + 1), giving you -12b - 6, and then on the another side of the equation, distribute -2 to (5 + 4b) giving you, -10 - 8b. now we need to put our coefficients on one side so we will add 8b to each side of the equation, giving us -6 = -10 - 8b + 12b, then we will add 10 to both sides of the equation giving us, 10 -6 = -8b +12b, this gives u 4 = 4b. then, you would solve for b, which equals 1.

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