Q1. The answer is x = 1, y = 1, z = 0
<span>(i) -2x+2y+3z=0
</span><span>(ii) -2x-y+z=-3
</span>(iii) <span>2x+3y+3z=5
</span><span>_________
Sum up the first and the third equation:
</span>(i) -2x+2y+3z=0
(iii) 2x+3y+3z=5
_________
5y + 6z = 5
Sum up the second and the third equation:
(ii) -2x-y+z=-3
(iii) 2x+3y+3z=5
_________
2y + 4z = 2
(iv) 5y + 6z = 5
(v) 2y + 4z = 2
________
Divide the fifth equation by 2
(iv) 5y + 6z = 5
(v) y + 2z = 1
________
Multiple the second equation by -3 and sum the equation
(iv) 5y + 6z = 5
(v) -3y - 6z = -3
________
2y = 2
y = 2/2 = 1
y + 2z = 1
1 + 2z = 1
2z = 1 - 1
2z = 0
z = 0
-2x-y+z=-3
-2x - 1 + 0 = -3
-2x = -3 + 1
-2x = -2
x = -2/-2 = 1
Q2. The answer is x = -37, y = -84, z = -35
<span>(i) x-y-z=-8
(ii) -4x+4y+5z=7
(iii) 2x+2z=4
______
</span>Divide the third equation by 2 and rewrite z in the term of x:
(iii) x+z=2
z = 2 - x
______
Substitute z from the third equation and express y in the term of x:
<span>x-y-(2-x)=-8
x - y - 2 + x = 8
2x - y = 10
y = 2x - 10
______
Substitute z from the third equation and y from the first equation into the second equation:
</span><span>-4x + 4y + 5z = 7
-4x + 4(2x - 10) + 5(2 - x) = 7
-4x + 8x - 40 + 10 - 5x = 7
-x -30 = 7
-x = 30 + 7
x = -37
y = 2x - 10 = 2*(-37) - 10 = -74 - 10 = -84
z = 2 - x = 2 - 37 = -35</span>
Answer:
See below
Step-by-step explanation:
The ratio of the secants is the same when set up as full length to external length.
Formula
MN/LN = QN/PN
Givens
LN = 22 + 14 = 36
MN = 14
PN = 32
QN = x
Solution
14/36 = x / (32) Multiply both sides by 32
14*32 / 36 = x Combine 14 and 32
448/36 = x Divide by 36 and switch
x = 12.4
Answers
PN (External) = 13 is the closest answer
Length LN = 36
<h3><u><em>My friends the answer is:</em></u></h3><h3><u><em>If 1 lunch =$2.50
</em></u></h3><h3><u><em>
2 lunches = $5.00 (2.50x2)
</em></u></h3><h3><u><em>
3 lunches =$7.50
</em></u></h3><h3><u><em>
4 lunches =$10.00
</em></u></h3><h3><u><em>
5 lunches= $12.50
</em></u></h3><h3><u><em>
Just add $2.50</em></u></h3>
The potential solutions of 
are 2 and -8.
<h3>Properties of Logarithms</h3>
From the properties of logarithms, you can rewrite logarithmic expressions.
The main properties are:
- Product Rule for Logarithms -
- Quotient Rule for Logarithms -
- Power Rule for Logarithms -
The exercise asks the potential solutions for . In this expression you can apply the Product Rule for Logarithms.
Now you should solve the quadratic equation.
Δ=
. Thus, x will be 
. Then:
The potential solutions are 2 and -8.
Read more about the properties of logarithms here:
brainly.com/question/14868849
