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3 years ago

Which two sets of events are most likely independent?

Mathematics

1 answer:

Bumek [7]3 years ago

5 0

Answer:

A and C

Step-by-step explanation:

Two events, A and B, are independent if the fact that A occurs does not affect the probability of B occurring.

Options B and D give events which are most likely to be dependent, because if a driver texts while driving affects the possibility that the driver can get into the accident and if a woman lives in Alaska affects she can have a heavy winter coat.

Options A and C are two sets of most likely independent events, because the girl's singing does not affect on her wish to become a lawyer and a man's hair doesn't depend on where his father lives.

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Quick! Easy Algebra 2 question, Rational expressions

madreJ [45]

The GCF is: 2x^2a

Hope this helps!

3 0

4 years ago

The leaves of a poison ivy plant are found in clusters of 3. One poison ivy plant has a total of 21 leaves. How many leaf cluste

svetlana [45]

Answer:

7 clusters

Step-by-step explanation:

Leaves in clusters of 3

One plant has 21 leaves

Divide 21 by 3

7 clusters of 3 leaves per cluster

To check, multiply 7 * 3, you get 21, answer is correct

5 0

4 years ago

Find the perimeter of the trapezoid <br> (5,1)( 5,-4) (1,1) (-2,-4)

klemol [59]

Answer:

i cold not find the answer

Step-by-step explanation:

6 0

3 years ago

A hiker in Africa discovers a skull that contains 32% of its original amount of C-14. find the age of the skull.

ziro4ka [17]

Answer:

9419.3 years.

Step-by-step explanation:

Let the initial amount of C-14 be 100 units.

We have been given that a hiker in Africa discovers a skull that contains 32% of its original amount of C-14. We are asked to find the age of the skull.

We will use half life formula to solve our given problem.

$A=a\cdot(\frac{1}{2})^{\frac{t}{h}}$ , where,

A = Amount left after t years,

a = Initial amount,

t = time,

h = Half life.

We know that half-life of C-14 is 5730 years.

32% of 100 units would be 32.

$32=100\cdot(\frac{1}{2})^{\frac{t}{5730}}$

$\frac{32}{100}=\frac{100\cdot(\frac{1}{2})^{\frac{t}{5730}}}{100}$

$0.32=(0.5)^{\frac{t}{5730}}$

Now, we will take natural log of both sides.

$\text{ln}(0.32)=\text{ln}((0.5)^{\frac{t}{5730}})$

Using log property $\text{ln}(a^b)=b\cdot\text{ln}(a)$ , we will get:

$\text{ln}(0.32)=\frac{t}{5730}\cdot \text{ln}(0.5)$

$\frac{\text{ln}(0.32)}{\cdot \text{ln}(0.5)}=\frac{t\cdot \text{ln}(0.5)}{5730\cdot \text{ln}(0.5)}$

$1.64385618977=\frac{t}{5730}$

$\frac{t}{5730}=1.64385618977$

$\frac{t}{5730}*5730=1.64385618977*5730$

$t=9419.295967$

$t\approx 9419.3$

Therefore, the age of skull is approximately 9419.3 years.

5 0

3 years ago

5. Based on this pattern, h human years, how old is your dog in dog years? In other words, if given any number to figure out the

rusak2 [61]

Hey there,

So. . .I saw that you chose a large dog. So if a large dog's expression would be $\boxed{(h-2) }$ . So if that would be that. . What would be a Humans, and determining his birth and age years. So. . This adult would be 75 years old and he is $\boxed{h-8}$ . The difference between those two ages is the one is 2 and the other is 8. So your answer could be 6.

~Jurgen

5 0

3 years ago

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