Answer:
Option A
The p-value is less than the significance level of 0.05 chosen and so we reject the null hypothesis H0 and can conclude that the proportion of the subjects who have the necessary qualities is less than 0.2.
Step-by-step explanation:
Normally, in hypothesis testing, the level of statistical significance is often expressed as the so-called p-value. We use p-values to make conclusions in significance testing. More specifically, we compare the p-value to a significance level "α" to make conclusions about our hypotheses.
If the p-value is lower than the significance level we chose, then we reject the null hypotheses H0 in favor of the alternative hypothesis Ha. However, if the p-value is greater than or equal to the significance level, then we fail to reject the null hypothesis H0
though this doesn't mean we accept H0 automatically.
Now, applying this to our question;
The p-value is 0.023 while the significance level is 0.05.
Thus,p-value is less than the significance level of 0.05 chosen and so we reject the null hypothesis H0 and can conclude that the proportion of the subjects who have the necessary qualities is less than 0.2.
The only option that is correct is option A.
Answer:
The correct answer is C
Step-by-step explanation:
In order to find the y-intercept, you need to first solve the inequality for y.
5x - 3y ≤ 15
-3y ≤ -5x + 15
y ≥ 5/3x - 5
Now we look at the constant at the end. Since that constant is -5, we know C to be the answer.
Answer:
$9.50
Step-by-step explanation:
$123.50/13 ladies
they each pay $9.50
Answer:
The min is at x=4/3
Step-by-step explanation:
Take the first derivitave. Set that equation equal to zero. Then take the second derivative. Take the x values and put them into the second derivative. If the value is +, that means a rel min. If it is -, that means rel max.
Answer:
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
substitute in the formula above
