Evaluate lim x --> 1 [(x^1000)-1]/[x-1]

1 answer:

6 0

Do L'hospital's rule.

 $\lim_{x \to 1} \frac{x^{1000}-1}{x-1}= \lim_{x \to 1} \frac{(x^{1000}-1)'}{(x-1)'}= \lim_{x \to 1} \frac{1000x^{999}}{1}=
\\
\\ \frac{1000\times1^{999}}{1}=\frac{1000}{1}=1000$

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Answers:
measure angle x = 40°
measure angle y = 35°
measure angle z = 55°

Explanation:
Part (a): getting angle x:
In triangle BED, we have:
measure angle BED = 90°
measure angle BDE = 50°
Therefore:
measure angle DBE = 180 - (90+50) = 40°
Now, we have angle DBE and angle GBF vertically opposite angles.
This means that they are both equal. Therefore angle GBF = 40°
Since angle GBF is x, therefore:
x = 40°

Part (b): getting angle y:
We know that the sum of measures of angles on a straight line is 180.
This means that:
angle GBF + angle GBC + angle CBE = 180
We have:
angle GBF = 40°
angle GBC = 105°
angle CBE = y
Therefore:
40 + 105 + y = 180
y = 35°

Part (c): getting angle z:
In triangle BCE, we have:
measure angle BCE = z
measure angle BEC = 90°
measure angle CBE = 35°
Therefore:
z + 90 + 35 = 180
z = 55°

Hope this helps :)