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arsen [322]
3 years ago
12

Evaluate lim x --> 1 [(x^1000)-1]/[x-1]

Mathematics
1 answer:
Ghella [55]3 years ago
6 0
<span>Do L'hospital's rule.

</span>\lim_{x \to 1}  \frac{x^{1000}-1}{x-1}=  \lim_{x \to 1}  \frac{(x^{1000}-1)'}{(x-1)'}=  \lim_{x \to 1}  \frac{1000x^{999}}{1}=&#10;\\&#10;\\ \frac{1000\times1^{999}}{1}=\frac{1000}{1}=1000<span>
</span>
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Answer:

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Step-by-step explanation:

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In this situation we have 2x² / x²

The powers of both are equal to each other therefore the horizontal asymptote will be at the coefficient of the numerator divided by the coefficient of the denominator.

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7 0
2 years ago
Y = x + 6<br> y=-x-4<br> Graph each equation then find a solution show your process.
Zina [86]

Answer:

(x,y) = (-5,1)

Step-by-step explanation:

USES SUBSTITUTION METHOD

Solving Steps:

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I hope this helped!!

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vlabodo [156]

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