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3 years ago

PLEASE HELP ME!

Mathematics

1 answer:

Tatiana [17]3 years ago

6 0

Answer:

TRUE

Step-by-step explanation:

2x + 0.8/y = z – 4

x = 7, y = 0.2, z = 22

2×7 + 0.8/0.2 = 22 - 4

14 + 4 = 18

18 = 18

TRUE.

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And we can set equal this derivate to 0 in order to find the critical point and we got:

$3.2 t-11= 0$

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And we can calculate the second derivate and we got:

$P''(t) = 3.2 >0$

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Step-by-step explanation:

For this case we have the following function:

$P(t) = 1.6 t^2 -11t +44$

Where P represent the annual net income for the period 2007-2011 and $2 \leq t \leq 7$

And t represent the time in years since the start of 2005

In order to find the lowet income we need to use the derivate, given by:

$P'(t) = 3.2 t -11$

And we can set equal this derivate to 0 in order to find the critical point and we got:

$3.2 t-11= 0$

$t = \frac{11}{3.2}= 3.4375$

And we can calculate the second derivate and we got:

$P''(t) = 3.2 >0$

So then w can conclude that the value of t = 3.4375 represent the minimum value for the function and we can replace in the original function and we got:

$P(3.4375) = 1.6(3.4375)^2 - (11*3.4375) +44 = 25.094$

So then the minimum annual income occurs at t = 3.43 (between 2008 and 2009) and the value is 25.094

5 0

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