T_n = 3 * T_(n-1)
Long way (always works!)
T_5 = 3*T_4,
T_4 = 3*T_3
T_3 = 3*T_2
T_2 = 3*T_1
T_5 = 3*3*3*3*T_1 = 81*T_1 = 81*8 = 648!
Short way (sometimes it works!)
T_n = 3^(n-1) * T_1 (this case is a geometric series of ratio-=3)
T_5 = 3^4*8 = 648
Answer: C
Step-by-step explanation:
Okay first set a comparison since the two triangles are similar
x-1/20=x-1+27/3x+8
x-1/20 = x+26/3x+8
cross multiply
20x+520=3x^2+8x-3x-8
3x^2-15x-528=0
3(x^2-5x-176)=0
im kinda lazy to factor this out so i used an online calculator right here but factor it out like a good kid
x=16, x=-11
it has to be positive so x=16
C
Answer:
h=v/πr²
Step-by-step explanation:
v=πr²h
v/π=r²h
v/πr²=h
Answer:
c
Step-by-step explanation:
-5/2
an example of how to write it is :)
