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Artemon [7]
3 years ago
12

Is -10x^8 a monomial.?

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
7 0
Yep! because there is no +,-, ect. sign. in total it is just one number
maxonik [38]3 years ago
6 0
-10x^8 is indeed a monomial, because there is only one term. There is nothing else added or subtracted.

There are three types of "nomials":

Monomials: such as the one you have, they only have one term
Example: y,  6x^2,  19084v^22341

Binomials: Equations with two terms
Example: x+1,  v+4w,  k+1021s

Polynomials: Equation with more than three terms (no limit)
Example: x+5+9z, t+9u+8v
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3 years ago
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(LOL, you TYPED them least to greatest!)

<span>Hope I helped! (Pick me as brainliest!)</span>
7 0
3 years ago
Abigail is studying for the school spelling bee. She already knows 154 words from the vocabulary list. Each day, she learns 31 a
Alex17521 [72]

Answer:

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Step-by-step explanation:

Since x represents the days and she learns 31 words per day you would need to multiply 31 and the number of days (x).

This would look like 31x.

We also know she already knew 154 from the beginning which means we just have to add 154.

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Hope this helps!

4 0
3 years ago
Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.
seropon [69]

Answer:

h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

Step-by-step explanation:

1) The Fundamental Theorem of Calculus in its first part, shows us a reciprocal relationship between Derivatives and Integration

g(x)=\int_{a}^{x}f(t)dt \:\:a\leqslant x\leqslant b

2) In this case, we'll need to find the derivative applying the chain rule. As it follows:

h(x)=\int_{a}^{x^{2}}\sqrt{5+r^{3}}\therefore h'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left (\int_{a}^{x^{2}}\sqrt{5+r^{3}}\right )\\h'(x)=\sqrt{5+r^{3}}\\Chain\:Rule:\\F'(x)=f'(g(x))*g'(x)\\h'=\sqrt{5+r^{3}}\Rightarrow h'(x)=\frac{1}{2}*(r^{3}+5)^{-\frac{1}{2}}*(3r^{2}+0)\Rightarrow h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

3) To test it, just integrate:

\int \frac{3r^{2}}{2\sqrt{r^3+5}}dr=\sqrt{r^{3}+5}+C

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3 years ago
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