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Inga [223]
3 years ago
10

Jayla buys and sells vintage clothing. She bought two blouses for $25.00 each and later sold them for $38.00 each. She bought th

ree skirts for $15.00 each and later sold them for $26.00 each. She bought five pairs of pants for $30.00 each and later sold them for $65.00 each.
Jayla’s expenses for purchasing the items were
Jayla’s revenue from the sale of the items was
Jayla’s total profit was
Mathematics
2 answers:
Klio2033 [76]3 years ago
7 0

Answer: Total expenses = $ 225

Total revenue = $479

Total profit = $254

Step-by-step explanation:

Since we have given that

Cost price of each blouse = $25.00

Cost price of two blouses is given by

25\times 2=\$50

Cost price of skirts = $15.00

Cost price of 3 skirts is given by

3\times 15\\\\=\$45.00

Cost price of pairs of pants = $30.00

Cost price of five pairs of pants is given by

30\times 5\\\\=\$150

so, Total expenses for purchasing the items were

Price of 2 blouses +Price of 3 skirts +Price of 5 pairs of pants

\$50+\$45+\$150\\\\=\$245

Selling price of each blouse = $38.00

Selling price of 2 blouses is given by

38\times 2\\\\=$76

Selling price of each skirt = $26.00

Selling price of 3 skirts is given by

26\times 3\\\\=\$78

Selling price of each pair of pants = $ 65.00

Selling price of 5 pairs of pants is given by

65\times 5\\\\=\$325

Total revenue from the sale of the items were

Sale of 2 blouses + Sale of 3 skirts +Sale of 5 pants

\$76+\$78+\$325\\\\=\$479

Total profit was

Total Revenue - Total Expenses

\$479-\$245\\\\=\$234

4vir4ik [10]3 years ago
5 0
Total expenses: $245.00
Total revenue: $479.00
Total profit $234.00
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A sample of 12 radon detectors of a certain type was selected, and each was exposed to 100 pCI/L of radon. The resulting reading
valkas [14]

Answer:

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

p_v =2*P(t_{11}  

Step-by-step explanation:

1) Data given and notation  

Data: 105.6, 90.9, 91.2, 96.9, 96.5, 91.3, 100.1, 105.0, 99.6, 107.7, 103.3, 92.4

We can calculate the sample mean and deviation for this data with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

The results obtained are:

\bar X=98.375 represent the sample mean  

s=0.6.109 represent the sample standard deviation  

n=12 sample size  

\mu_o =100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 100pCL/L, the system of hypothesis are :  

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

4) P-value  

First we need to find the degrees of freedom for the statistic given by:

df=n-1=12-1=11

Since is a two sided test the p value would given by:  

p_v =2*P(t_{11}  

5) Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significant different from 100 at 5% of significance.  

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Answer:

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Step-by-step explanation:

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half of 3 is 1.5

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

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