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NNADVOKAT [17]
3 years ago
8

From his home, Clayton would have to walk 4 miles north to get to his friend Miki's house and 1 mile east to get to his friend D

anny's house. One day, Clayton walked from his home to Danny's house. Together, Danny and Clayton cut directly through the field that separated them from Miki's house. When they finished playing at Miki's, Clayton walked back home. In all, how far did Clayton walk? If necessary, round to the nearest tenth.
Mathematics
1 answer:
iren2701 [21]3 years ago
7 0
The houses form a right triangle. Using a²+b²=c² you will find that the distance from Clayton’s house to Danny’s would be 4.1 miles. Adding it all up, the distance would be 9.1 miles of walking.
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Step-by-step explanation:

y^2 = x^2 + 5​

Rewriting

y^2 - x^2 = 5

This is a hyperbola

We can use the vertical line test to show that it is not a function since a vertical line passes through more than one point.

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A line passes through (2, 8) and (4, 12). Which equation best represents the line?
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3 years ago
Read 2 more answers
Can someone help me?
mestny [16]

Answer:

Step-by-step explanation:

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Now that we know these we can start using the trig functions

sin = y

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And the other functions would be the reciprocal of these

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6 0
3 years ago
I have just one question, could someone please answer it?? (see linked file)
Annette [7]

The solution is x=1 and y=-2

Further explanation:

Given equations are:

\frac{7}{2}x-\frac{1}{2}y=\frac{9}{2}\\3x-y=5

Multiplying equation no. 1 with 2 will give us:

7x-y=9       Eqn 3

From equation no 2:

3x-y=5\\-y=5-3x\\y=3x-5

Putting the value of y in eqn 3

7x-(3x-5)=9\\7x-3x+5=9\\4x=9-5\\4x=4\\\frac{4x}{4}=\frac{4}{4}\\x=1\\Putting\ x=1\ in\ equation\ 2\\3(1)-y=5\\3-y=5\\-y=5-3\\-y=2\\y=-2\\

The solution is x=1 and y=-2

Keywords: Linear equations, Solution set

Learn more about linear equations at:

  • brainly.com/question/561665
  • brainly.com/question/537998

#LearnwithBrainly

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