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2 years ago

Need help plz what is a hole

Mathematics

1 answer:

jolli1 [7]2 years ago

8 0

Answer:

Statements 1,4&5

Step-by-step explanation:

A hole is when both, numerator and denominator, of a fraction become 0 (zero).

This would happen when the numerator and denominator have a common factor.

Example:

(2x+4)/(x+2)

= [2(x+2)]/(x+2) = 2

Although the fraction can be simplified, there's a hole at x = -2.

x = -2 will not be part of the domain.

The hole is represented by an open circle.

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Which is the equation of a hyperbola centered at the origin with vertex (0, sqrt 12 ) that passes through (2 sqrt 3,6)

mina [271]

Answer:

y-intercept = a +y^2/12 term in it.

Then for y=6, you have

.. 6^2/12 -x^2/b = 1

.. 2 = x^2/b

.. b = x^2/2

If your point is (2√3, 6), then this is

.. b = (2√3)^2/2 = 12/2 = 6

Then the hyperbola's equation is

.. y^2/12 -x^2/6 = 1 . . . . . . . . selection D

Step-by-step explanation:

6 0

3 years ago

I need help it's so confusing!

jasenka [17]

Try looking up the answer

5 0

2 years ago

4. If a warehouse holds 300 boxes, and a truck holds 25 boxes. How many truckloads will it take to fill up one warehouse?

Brut [27]

It will take 12 truckloads to fill up one warehouse. Hope this helps.

8 0

3 years ago

Read 2 more answers

Which of the following functions has a period of 8 π ?

KengaRu [80]

<h3>Answer: Choice B</h3>

Explanation:

The general template of a sine function is

y = Asin(B(x-C))+D

The value of B is the only thing that determines the period T. We ignore every other term.

It turns out that T = 2pi/B which can be solved to B = 2pi/T

Plug in the given period of T = 8pi and compute to get

B = 2pi/T

B = (2pi)/(8pi)

B = 2/8

B = 1/4

This means that the term out front of the x is 1/4 and the equation must be $y = \sin\left(\frac{1}{4}x\right)$ which matches with answer choice B.

4 0

2 years ago

Blake and Ned work for home remodeling business they are putting the final touches on a home they renovated. working alone Blake

stiks02 [169]

Answer:

3.6 hours

Step-by-step explanation:

Blake can do work in hours = 9

Blake can do a part of work in 1 hour = $\frac{1}{9}$

Ned can paint the same room in six hours.

Ned can do a part of work in 1 hour = $\frac{1}{6}$

They can do a part of work together in 1 hour = $\frac{1}{9}+\frac{1}{6}$

= $\frac{5}{18}$

Now they can do $\frac{5}{18}$ part of work in hour = 1

So, they can do whole work in hours = $\frac{1}{\frac{5}{18}}$

= $3.6$

Hence it will take 3.6 hours to paint the room if they work together.

6 0

2 years ago