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3 years ago

Need help plz what is a hole

Mathematics

1 answer:

jolli1 [7]3 years ago

8 0

Answer:

Statements 1,4&5

Step-by-step explanation:

A hole is when both, numerator and denominator, of a fraction become 0 (zero).

This would happen when the numerator and denominator have a common factor.

Example:

(2x+4)/(x+2)

= [2(x+2)]/(x+2) = 2

Although the fraction can be simplified, there's a hole at x = -2.

x = -2 will not be part of the domain.

The hole is represented by an open circle.

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URGENT WILL MARK BRAINLIEST

DiKsa [7]

Answer:

x=2, y=2

Step-by-step explanation:

3x + y = 8

2x + 4y = 12

Multiply the first equation by -4

-12x -4y = -32

Then add to the second equation

-12x -4y = -32

2x + 4y = 12

------------------------

-10x + 0y = -20

-10x = -20

Divide by -10

-10x/-10 = -20/-10

x =2

Now find y

3x+y = 8

3(2)+y = 8

6+y = 8

y = 8-6

y =2

3 0

3 years ago

Read 2 more answers

If you need two gallons, which store should you buy from? First store Second store They are the same price There is not enough i

Reika [66]

Not enough info. We dont have the prices from the stores

4 0

3 years ago

– 6 x + 4 < 29 answer?

svlad2 [7]

Answer:

its 847>×+18 enjoy hope it work

4 0

3 years ago

Need help #3. The answer is shown, but I don’t know how to get to the answer. Please teach and show steps.

Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

We are given a right triangle with a base of x feet and a height of h feet, where x is constant and h changes with respect to time t.

The angle in radians is defined by:

$\displaystyle \tan(\theta)=\frac{h}{x}$

And we want to find the relationship that describes dθ/dt and dh/dt.

So, we will differentiate both sides with respect to t where x is a constant:

$\displaystyle \frac{d}{dt}[\tan(\theta)]=\frac{d}{dt}\Big[\frac{h}{x}\Big]$

Differentiate. Apply the chain rule on the left. Again, remember that x is just a constant, so we can move it outside the derivative operator. Therefore:

$\displaystyle \sec^2(\theta)\frac{d\theta}{dt}=\frac{1}{x}\frac{dh}{dt}$

Since we know that tan(θ)=h/x, h is the opposite side of our triangle and x is the adjacent. Therefore, by the Pythagorean Theorem, our hypotenuse will be:

$\text{Hypotenuse}=\sqrt{h^2+x^2}$

Since secant is the ratio of the hypotenuse to adjacent:

$\displaystyle \sec(\theta)=\frac{\sqrt{h^2+x^2}}{x}$

So:

$\displaystyle \sec^2(\theta)=\frac{x^2+h^2}{x^2}$

By substitution, we have:

$\displaystyle \Big(\frac{x^2+h^2}{x^2}\Big)\frac{d\theta}{dt}=\frac{1}{x}\frac{dh}{dt}$

By multiplying both sides by the reciprocal of the term on the left:

$\displaystyle \frac{d\theta}{dt}=\frac{1}{x}\Big(\frac{x^2}{x^2+h^2}\Big)\frac{dh}{dt}$

Therefore:

$\displaystyle \frac{d\theta}{dt}=\frac{x}{x^2+h^2}\frac{dh}{dt}$

Our answer is A.

3 0

3 years ago

If n is "the number," which equation could be used to solve for the number?

Alla [95]

Infinite solutions ig without one or more actual number or variable there is no way to get one solid answer. (Im not positive ik im probably very wrong but this is just my guess by looking at it Im barely passing math as is)

8 0

3 years ago