So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
Answer:
3rd box
Step-by-step explanation:
BRAINLIEST PLEASE
Answer:

Step-by-step explanation:
see the attached figure with letters to better understand the problem
step 1
In the right triangle ACD
Find the length side AC
Applying the Pythagorean Theorem

substitute the given values



simplify

step 2
In the right triangle ACD
Find the cosine of angle CAD

substitute the given values

----> equation A
step 3
In the right triangle ABC
Find the cosine of angle BAC

substitute the given values
----> equation B
step 4
Find the value of x
In this problem
----> is the same angle
so
equate equation A and equation B
solve for x
Multiply in cross


step 5
Find the length of BC
In the right triangle BCD
Applying the Pythagorean Theorem

substitute the given values



simplify

Answer:
15
Step-by-step explanation:
If y is 20 when x is 5 then x is always 1/4 of y
60*(1/4)=15