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MA_775_DIABLO [31]
3 years ago
12

(20 POINTS AND BRAINLIEST)

Mathematics
2 answers:
Mamont248 [21]3 years ago
7 0

Answer:

see below

Step-by-step explanation:

a) y = 6x + 25  (because the 25 is the initial fee)

b) x = 10, so:  

= 6 * 10 + 25

= $85

c) x = 7, so:

= 6 * 7 + 25  

= $69

Hope this helps!

Evgen [1.6K]3 years ago
3 0

Answer:

a) The equation is y = 6x + 25 since the 25 is the initial fee.

b) We plug in 10 for x. 6 * 10 + 25 = $85.

c) We plug in 7 for x and get 6 * 7 + 25  = $69.

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Find the dimensions of a rectangle with a perimeter of 52cm if it’s length is 4cm more than its width
Zina [86]
So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
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nika2105 [10]

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Step-by-step explanation:

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8 0
3 years ago
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Fine length of BC on the following photo.
MrMuchimi

Answer:

BC=4\sqrt{5}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

AC^2=AD^2+DC^2

substitute the given values

AC^2=16^2+8^2

AC^2=320

AC=\sqrt{320}\ units

simplify

AC=8\sqrt{5}\ units

step 2

In the right triangle ACD

Find the cosine of angle CAD

cos(\angle CAD)=\frac{AD}{AC}

substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

cos(\angle CAD)=\frac{2}{\sqrt{5}} ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

cos(\angle BAC)=\frac{AC}{AB}

substitute the given values

cos(\angle BAC)=\frac{8\sqrt{5}}{16+x} ----> equation B

step 4

Find the value of x

In this problem

\angle CAD=\angle BAC ----> is the same angle

so

equate equation A and equation B

\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}

solve for x

Multiply in cross

(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units

DB=4\ units

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

BC^2=DC^2+DB^2

substitute the given values

BC^2=8^2+4^2

BC^2=80

BC=\sqrt{80}\ units

simplify

BC=4\sqrt{5}\ units

7 0
3 years ago
If y is 20 when x is 5 find x when y is 60
Verdich [7]

Answer:

15

Step-by-step explanation:

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Find the value of x in the following figure.<br> (a)<br> 60°<br> (2x + 40°<br> R
miskamm [114]
60

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3 years ago
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