Question

Item 25

Answer 1

Answer:

$m =\frac{y_2 -y_1}{x_2-x_1}= \frac{5425-3733}{3-0}= 564$

Now we can use the value for 1994 and we can find the intercept like this:

$3733 = 564*0 +b$

And solving for b we got:

$b = 3733 -0= 3733$

So then oir model would be given by:

$y= 564x +3733$

Option C

Step-by-step explanation:

For this case we want to create a linear function for the the value of  the investment in the vear x, where x =0 represents 1994.

We know that for 1994 (x= 0) the value is y = $3733 and for 1997 (x=3) the value of y = $5425

We want to find a model given by:

$y = mx +b$

Where m is the slope and b the intercept. We can find the slope with this formula:

$m =\frac{y_2 -y_1}{x_2-x_1}= \frac{5425-3733}{3-0}= 564$

Now we can use the value for 1994 and we can find the intercept like this:

$3733 = 564*0 +b$

And solving for b we got:

$b = 3733 -0= 3733$

So then oir model would be given by:

$y= 564x +3733$

Option C