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Arte-miy333 [17]
3 years ago
7

In the accompanying figure, triangle ABC has coordinates A(0,3), B(7,3), C(7,7). What is the area of triangle ABC in square unit

s?

Mathematics
1 answer:
ElenaW [278]3 years ago
4 0

We know area of triangle = \frac{1}{2}  * base * height

In triangle ABC , AB is the base and BC is the height

Now we find the distance between A and B

Distance formula is \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}

A(0,3), B(7,3)

Distance AB = \sqrt{(7-0)^2 + (3-3)^2}

= \sqrt{(7)^2 } = 7

B(7,3), C(7,7)

Distance BC = \sqrt{(7-7)^2 + (7-3)^2}

= \sqrt{(4)^2 } = 4

area of triangle = \frac{1}{2}  * base * height

area of triangle = \frac{1}{2}  * AB * BC

= \frac{1}{2}  * 7 * 4 = 14 units ^2

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