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Arte-miy333 [17]

3 years ago

7

In the accompanying figure, triangle ABC has coordinates A(0,3), B(7,3), C(7,7). What is the area of triangle ABC in square unit

s?

1 answer:

ElenaW [278]3 years ago

4 0

We know area of triangle = $\frac{1}{2} * base * height$

In triangle ABC , AB is the base and BC is the height

Now we find the distance between A and B

Distance formula is $\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

A(0,3), B(7,3)

Distance AB = $\sqrt{(7-0)^2 + (3-3)^2}$

= $\sqrt{(7)^2 }$ = 7

B(7,3), C(7,7)

Distance BC = $\sqrt{(7-7)^2 + (7-3)^2}$

= $\sqrt{(4)^2 }$ = 4

area of triangle = $\frac{1}{2} * base * height$

area of triangle = $\frac{1}{2} * AB * BC$

= $\frac{1}{2} * 7 * 4$ = 14 $units ^2$

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A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

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Step-by-step explanation:

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The weight of the water is $W_w = 42 lb$

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The rate of the leak is $r = 0.15 lb/s$

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