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Nesterboy [21]
1 year ago
14

The ___ is the average of the sum of the squared differences of the mean from each element in a set of numerical data.

Mathematics
1 answer:
Bess [88]1 year ago
4 0

Answer:

Variance.

Step-by-step explanation:

that is the variance of the data.

The square root of the variance is the Standard Deviation.

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If x=-1\3 is a zero of a polynomial p(x)=27xcube -axsquare -x+3 then find the value of a
antoniya [11.8K]

Answer:

a = 21

Step-by-step explanation:

If x = h is a zero of a polynomial then f(h) = 0, thus

p(- \frac{1}{3} ) = 27( - \frac{1}{3} )³ - a(- \frac{1}{3} ) - (- \frac{1}{3} ) + 3 = 0, that is

27 (- \frac{1}{27} ) - \frac{1}{9} a + \frac{1}{3} + 3 = 0

- 1 - \frac{1}{9} a + \frac{10}{3} = 0 ( multiply through by 9 to clear the fractions )

- 9 - a + 30 = 0

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5 0
2 years ago
Solve each equation by factoring,<br>x² - 2x - 15 = 0​
valina [46]

Answer:

x=−3 or x=5

Step-by-step explanation:

x2−2x−15=0

Step 1: Factor left side of equation.

(x+3)(x−5)=0

Step 2: Set factors equal to 0.

x+3=0 or x−5=0

x=−3 or x=5

7 0
2 years ago
How many centimeters are in 10 feet given that 1 inch = 2.54 cm
lions [1.4K]
304.8 centimeters is the answer to this question.

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2 years ago
Amar wants to make lemonade for a birthday party. He wants to mix 12 tablespoons of sugar in water. He only has a teaspoon which
o-na [289]

Answer:48

Step-by-step explanation:

Given

Amar wants 12 tablespoons of sugar in water.

Amar has teaspoon whose four times is equivalent to 1 tablespoon

i.e. 4\ \text{teaspoon}\equiv 1\ \text{tablespoon}

therefore

12 tablespoon is 4\times 12

\Rightarrow 4\times 12

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So, amar need to add 48\ \text{teaspoons} for lemonade

8 0
3 years ago
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Margarita [4]
Check the picture below.

so, the center of the circle is the midpoint of that diametrical segment, and half that length is the radius.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{3-2}{2}~~,~~\cfrac{8-4}{2} \right)\implies \left( \frac{1}{2}~,~2 \right)\impliedby center

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}~~~ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;d=\sqrt{[3-(-2)]^2+[8-(-4)]^2}\implies d=\sqrt{(3+2)^2+(8+4)^2}&#10;\\\\\\&#10;d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13\qquad\qquad \qquad  \stackrel{radius}{\frac{13}{2}}

\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{\frac{1}{2}}{ h},\stackrel{2}{ k})\qquad \qquad &#10;radius=\stackrel{\frac{13}{2}}{ r}&#10;\\\\\\&#10;\left( x-\frac{1}{2} \right)^2+(y-2)^2=\left( \frac{13}{2} \right)^2\implies \left( x-\frac{1}{2} \right)^2+(y-2)^2=\frac{169}{4}

3 0
3 years ago
Read 2 more answers
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