Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
Step-by-step explanation:
may be those can be QT and QN
Answer:
trigonometry
Step-by-step explanation:
hope this helps lovely
Answer:
950 and 950
Step-by-step explanation:
Lets just get this done :
10 x 50 = 500
9 x 50 = 450
500 + 450 =
950
---
20 x 50 = 1000
1000 - 50 = 950
Hope this helps!
20 more than what they played or 20 more than what they lost?
