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matrenka [14]
2 years ago
12

Plz what is the answer?

Mathematics
1 answer:
Musya8 [376]2 years ago
4 0

Answer:

33

Step-by-step explanation:

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Last year Tammy had $4,500 to invest in two savings accounts. One account earns 7% simple annual interest, and the other account
Nat2105 [25]
Let x be the amount invested at 7% and y the amount invested at 6%

We know that the yearly interest earned = 0.07(x) and 0.06(y)
x+y =4500 
0.07x +0.06 y =290
Solving the equations will give , x = $2,000 and y=$2,500

7 0
3 years ago
Let ​ f(x) = 4(x^2) - 3x
posledela

Answer:

(f+g)(x)=5x²-4x+3

(f-g)(x)=3x²-2x+3

(fg)(x)=4x^4-7x^3+15x^2-9x

\frac{f}{g}(x) =\frac{4x^2-3x}{x^2-x+3}

Step-by-step explanation:

Given that,

f(x)=4x²-3x

g(x)=x²-x+3

(f+g)(x)

=f(x)+g(x)

=4x²-3x+x²-x+3

=(4x²+x²)+(-3x-x)+3   [ combined the like terms]

=5x²-4x+3

(f-g)(x)

=f(x)-g(x)

=4x²-3x-(x²-x+3)

=4x²-3x-x²+x-3

=(4x²-x²)+(-3x+x)-3   [ combined the like terms]

=3x²-2x+3

(fg)(x)

=f(x).g(x)

=(4x²-3x).(x²-x+3)

=4x²(x²-x+3)-3x(x²-x+3)

=4x^4-4x^3+12x^2-3x^3+3x^2-9x

=4x^4+(-4x^3-3x^3)+(12x^2+3x^2)-9x

=4x^4-7x^3+15x^2-9x

\frac{f}{g}(x)

=\frac{f(x)}{g(x)}

=\frac{4x^2-3x}{x^2-x+3}

7 0
3 years ago
1+1+2+3+4+5+6+7+8+9=?
Doss [256]

Answer:

46

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the value of y.
Murrr4er [49]
I don't feel like working it out/ maybe someone will give you the answer/ but basically you would set
(3y + 1)
and add it to
(8x - 61)
to equal 180( which is the degree of a line
so it looks like this:
(3y + 1) + (8x - 61) = 180
and then solve( tell me if you need more clarification)
7 0
3 years ago
Read 2 more answers
High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capa
Nikolay [14]

Using the normal distribution, it is found that a student has to score 1.08 standard deviations above the mean to be publicly recognized.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mustandard deviation \sigmaz-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

The top 14% of the scores are given by scores above the 86th percentile, which corresponds to Z = 1.08, hence, a student has to score 1.08 standard deviations above the mean to be publicly recognized.

More can be learned about the normal distribution at brainly.com/question/24663213

4 0
2 years ago
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