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Svetllana [295]
3 years ago
5

Solve the triangle. a = 10, b = 23, C = 95°

Mathematics
1 answer:
gayaneshka [121]3 years ago
3 0
C² = a² + b² - (2ab * cosC) 
<span>c² = 10² + 23² - (2 * 10 * 23 * cos95) </span>
<span>c² = 100 + 529 - (460 * -.08715) </span>
<span>c² = 629 - (-40.1) </span>
<span>c² = 669.1 </span>
<span>c = 25.87 </span>

<span>(Sin C) / C = (Sin A) / A </span>
<span>(Sin 95) / 25.87 = SinA / 10, Remember 0 < A < 85 </span>
<span>(10 * Sin95) / 25.87 = Sin A </span>
<span>A = arcsin ((10 * sin95) / 25.87) </span>
<span>A = 22.65º </span>

<span>B = 180 - A - C </span>
<span>B = 180 - 95 - 22.65 </span>
<span>B = 62.35º </span>

<span>I hope this helps. Have a good day.</span>
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Answer:

\Huge \boxed{X

Step-by-step explanation:

To solve this problem, first you have to isolate it on one side of the equation. Remember to solve this problem, find represents the solution of 5(x+5)<85.

First, you divide by 5 from both sides.

\displaystyle \frac{5(x+5)}{5}

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Mrrafil [7]

Answer:

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