Question

Solve the triangle. a = 10, b = 23, C = 95°

Answer 1

C² = a² + b² - (2ab * cosC) 
c² = 10² + 23² - (2 * 10 * 23 * cos95) 
c² = 100 + 529 - (460 * -.08715) 
c² = 629 - (-40.1) 
c² = 669.1 
c = 25.87 

(Sin C) / C = (Sin A) / A 
(Sin 95) / 25.87 = SinA / 10, Remember 0 < A < 85 
(10 * Sin95) / 25.87 = Sin A 
A = arcsin ((10 * sin95) / 25.87) 
A = 22.65º 

B = 180 - A - C 
B = 180 - 95 - 22.65 
B = 62.35º 

I hope this helps. Have a good day.