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WINSTONCH [101]
3 years ago
10

Bert is planning to open a savings account that earns 1.6% simple interest yearly. He wants to earn exactly $144 in interest aft

er 3 years. How much money should he deposit?
Mathematics
1 answer:
V125BC [204]3 years ago
3 0
I=PRT
144=(x)(0.016)(3) 
144=0.048x
x    =3000

Therefore Bert will need to invest $3000 to earn $144 on interest from a 1.6% rate for 3 years.

I hope this helps you.
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Y is directly proportional to x, and y=56 when x=7. find the value of y when x=4.
podryga [215]
Y=kx
when y=56, x=7
56=7k
k=8
when x=4
y=8(4)
y=32
value of y=32
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Given the following table, what is the quadratic equation?
rusak2 [61]

Answer:

144322221111155554444444333222222

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State if the two triangles are congruent. If they are, state how you know.
Elodia [21]
17. Yes!! SAS theorem
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19. Yes !! SSS theorem
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2 years ago
Complete the ordered pairs (9,...), (..., 71) for the equation.<br> y= 10X-9
zaharov [31]

Answer:

(9, <u>81</u>) (<u>8</u>, 71)

Step-by-step explanation:

My explanation is in the picture. All I did was replace the known variable with the proper letter!

4 0
3 years ago
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Oliga [24]

Answer:

\displaystyle 1)48.2    \:  \: \text{sec}

\rm \displaystyle  2)3021.6 \: m

Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

\displaystyle  - 4.9 {t}^{2}  + 229t + 346 = 0

to solve the equation can consider the quadratic formula given by

\displaystyle x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4 ac} }{2a}

so let our a,b and c be -4.9,229 and 346 Thus substitute:

\rm\displaystyle t =  \frac{ - (229) \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

remove parentheses:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

simplify square:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}

simplify multiplication:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 6781.6} }{ - 9.8}

simplify Substraction:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 45659.4} }{ - 9.8}

by simplifying we acquire:

\displaystyle t = 48.2  \:  \:  \: \text{and} \quad  - 1.5

since time can't be negative

\displaystyle t = 48.2

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

\displaystyle x _{  \text{max}} =  \frac{ - b}{2a}

let a and b be -4.9 and 229 respectively thus substitute:

\displaystyle t _{  \text{max}} =  \frac{ - 229}{2( - 4.9)}

simplify which yields:

\displaystyle t _{  \text{max}} =  23.4

now plug in the maximum t to the function:

\rm \displaystyle  h(23.4)- 4.9 {(23.4)}^{2}  + 229(23.4)+ 346

simplify:

\rm \displaystyle  h(23.4)  =  3021.6

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

5 0
3 years ago
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