Answer:
a ) 
,
b ) 
Step-by-step explanation:
This is a nice and short question we have here.
Given that a bag has n counters, and that one counter is blue, respectively the rest is red, if two counters are taken at random there isn't a definite percentage that one of the counters chosen is red or blue, but there is a fractional representation of this.
We could express n ( number of counters ) to form a probability of 2 / n. As you can see, two counters are taken at random over n counters, and thus we derived this fraction.
a )
____
Now we have this second part -
Therefore, there are 15 red counters. Hope that helps!
The answer is true. Pretty darn sure
Answer:
The scale factors that make figure smaller are the option D. -0.5 and the option E. 0.25
Step-by-step explanation:
we know that
If the absolute value of the scale factor is greater than 1, then the image will be larger than the pre-image.
If the absolute value of the scale factor is less than 1, then the image will be smaller than the pre-image.
If the absolute value of the scale factor is equal to 1, then the image will be the same size than the pre-image.
Additionally, a negative scale factor causes the dilation to rotate 180 degrees
therefore
In this problem
The scale factors that make figure smaller are the option D. -0.5 and the option E 0.25
Answer:
Step-by-step explanation:
The value of x is 7 ⇒ 1st answer
Step-by-step explanation:
* Lets revise a fact in the circle
- The two tangents drawn from a point out side the circle are equal
∵ RSTUV is circumscribed about a circle
∴ Each side of the pentagon is a tangent to the circle
- Look to the attached figure to know how we will solve the problem
- Each tangent divided into two parts
# RS = x + y
∵ RS = 8
∴ x + y = 8 ⇒ (1)
# RV = x + n
∵ RV = 12
∴ x + n = 12 ⇒ (2)
- Subtract (2) from (1)
∴ y - n = -4 ⇒ (3)
# ST = y + z
∵ ST = 12
∴ y + z = 12 ⇒ (4)
# TU = z + m
∵ TU = 15
∴ z + m = 15 ⇒ (5)
- Subtract (5) from (4)
∴ y - m = -3 ⇒ (6)
# UV = m + n
∵ UV = 9
∴ m + n = 9 ⇒ (7)
- Add (6) and (7)
∴ y + n = 6 ⇒ (8)
- Lets solve equation (3) and equation (8) to find y
∵ y - n = -4 ⇒ (3)
∵ y + n = 6 ⇒ (8)
- Add (3) and (8)
∴ 2y = 2 ⇒ divide two sises by 2
∴ y = 1
- Lets substitute the value of y in equation (1)
∵ x + y = 8 ⇒ (1)
∵ y = 1
∴ x + 1 = 8 ⇒ subtract (1) from both sides
∴ x = 7
* The value of x is 7
plz mark me as brainlyist thxx
Answer:
x^3 +8x^2 +13
Step-by-step explanation:
(6x^2 - 3 + 5x^3) - (4x^3 - 2x^2 - 16)
Distribute the minus sign
6x^2 - 3 + 5x^3 -4x^3 + 2x^2 + 16
Combine like terms
x^3 +8x^2 +13
